Answer:
c = 25m + 40
Step-by-step explanation:
Answer:
cdab
Step-by-step explanation:
Answer:
21 feet
Step-by-step explanation:
Given :
Height of the tripod above the ground = 5 ft
Elevation = 8°
Distance of the tree from the tripod = 120 ft
Therefore from the figure, we can find the height of the tress as:
![$\tan 8 ^\circ = \frac{BC}{AB}$](https://tex.z-dn.net/?f=%24%5Ctan%208%20%5E%5Ccirc%20%3D%20%5Cfrac%7BBC%7D%7BAB%7D%24)
![$0.1405 = \frac{BC}{120}$](https://tex.z-dn.net/?f=%240.1405%20%20%3D%20%5Cfrac%7BBC%7D%7B120%7D%24)
∴ BC ≈ 16
Therefore, CE = BC+BE
= 16 + 5
= 21
Therefore the height of the tree is 21 feet.
It would be 20.15 because the 65% of 31 is 20.15
Acceleration is simplified by assuming it is the constant -g
a=-g we integrate this with respect to time to get v...
v=-gt+C where C is the initial velocity in this case 14ft/s so
v=-gt+14 integrate again to get the height function
h=(-gt^2)/2 +14t +C we are not given an initial height so C is 0
h(t)=14t-gt^2/2 letting g=32 and neatening up a bit...
h(t)=14t-16t^2