Answer:
{0, 4 and -3}
Step-by-step explanation:
f(x)=x^3-x^2-12x can be factored, starting by taking out the 'x' factor:
f(x)=x^3-x^2-12x = x(x^2 - x - 12), and then by factoring the quadratic:
f(x) = x(x - 4)(x + 3) = 0
Then the zeros are {0, 4 and -3}.
Answer:
y=18.2
Step-by-step explanation:
-3x+5y=22
-3(37-14)+5y=22
-69+5y=22
5y=91
y=18.2
check:
-3(37-14)+5(18.2)=22
-69+91=22
22=22
-5g - 3/h-3 + 7g +9/h-3 = -5g + 7g -3/h-3 + 9/h-3 = 2g + (9 - 3)/(h-3) =
= 2g + 6/(h-3) if we want it as one fraction it would be:
2g + 6/(h-3) = [2g(h-3) + 6]/(h-3) =
Substitute the 0 in for y:
-3x - 3(0) = -12
-3x - 0 = -12
-3x = -12
Divide by -3:
-12/-3= 4
Answer:
x = 4
Answer:
I believe C
Step-by-step explanation:
hope this helps
