Answer:
a) probability that neither is Tay-Sachs carrier is 0.9298
b) the probability that both are carriers is 0.001276
Step-by-step explanation:
Given that;
1 in 28 people of Ashkenazi jewish descent are Tay-Sachs carrier.
so P(Carrier) = 1/28 =
also P( Not a carrier) = 1 - 1/28 = 0.9643
Now After Sampling 1 man and 1 woman from the population;
a)
the probability neither is Tay-Sachs carrier
P( Neither is a Carrier) = 27/28 × 27/28 = 0.9298
Therefore probability that neither is Tay-Sachs carrier is 0.9298
b)
the probability both are carriers
P( Both are Carriers) = 1/28 × 1/28 = 0.001276
Therefore the probability that both are carriers is 0.001276
Rise/Run=2/4= 1/2, the answer would be 1/2.
f(x) = 2 + 3cos(10π(x - 3))
f(47) = 2 + 3cos(10(3.14)(47 - 3))
f(47) = 2 + 3cos(31.4(45))
f(47) = 2 + 3cos(1413)
f(47) = 2 + 3(0.891006524)
f(47) = 2 + 2.673019573
f(47) = 4.673019573
-(-2) is 2
Because -1 and -2 make a +2
