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Soloha48 [4]
3 years ago
10

Rewrite the equation 4x + 5x2 = 8x – 7 in standard form and

Mathematics
1 answer:
Makovka662 [10]3 years ago
4 0

Answer:

The correct option is a=5, b = -4, c=7 ....

Step-by-step explanation:

The standard form is ax²+bx+c=0

where a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

The given expression is:

4x + 5x2 = 8x – 7

To make it a standard equation we will move all the values to the left hand side and 0 will be left at the right hand side.

4x+5x²-8x+7=0

Now solve the like terms and arrange the equation according to the standard form:

ax²+bx+c=0

5x² - 4x +7 =0

Here a = 5

b = -4

c= 7

Thus the correct option is a=5, b = -4, c=7 ....

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3 years ago
Sam has three identical tennis balls with a diameter of 2.7 inches. Determine the volume of all three tennis balls?
melamori03 [73]

Answer:

They are 30.93 in³ altogether.

Step-by-step explanation: V = 4/3 π r³

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3 0
3 years ago
Suppose that angle P = 3x + 14 and angle Q = 3x - 27. If these angles are supplementary, angle Q would need to be ___ degrees.
adelina 88 [10]

Answer:

Q = 69.5 degrees

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3x + 14 + 3x - 27 = 180

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5 0
3 years ago
one electrician charges a $50 service call fee plus $25 per hour for labor. Another electrician charges a $35 service call fee p
tangare [24]

Answer:

The answer would be 6.

Step-by-step explanation:

First, we need to make equations for these electricians fee's.

Electrician one: Y=25x+50, 50 is the upfront cost and 25 is the cost per hour for work.

Electrician two: Y=27.50x+35, It is the same thing for these numbers.

Then you need to incert numbers into the X place. Y will be your answer.

Y=25(6)+50, Y=150+50, Y=200

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The answer would be 6. If both the electricians worked for 6 hours each, their prices would be equal.

3 0
3 years ago
The volume of a sphere is 1928pi m^3. what is the surface area of the sphere to the nears tenth
nika2105 [10]
\bf \begin{array}{llll}
\textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}\\
----------\\
\textit{surface area of a sphere}\\\\
S=4\pi r^2
\end{array}\qquad r=radius\\\\
-----------------------------\\\\
V=1928\implies 1928=\cfrac{4\pi r^3}{3}\implies \cfrac{3\cdot 1928}{4\pi }=r^3
\\\\\\
\sqrt[3]{\cfrac{3\cdot 1928}{4\pi }}=\boxed{r}\qquad thus
\\\\\\
S=4\pi \left( \boxed{\sqrt[3]{\cfrac{3\cdot 1928}{4\pi }}} \right)^2
5 0
3 years ago
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