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AlladinOne [14]

3 years ago

5

Please help me! graph y=3/4x-1/2

2 answers:

Nat2105 [25]3 years ago

6 0

Answer:

in attachment

Step-by-step explanation:

An easy-ish way to graph something in slope-intercept form is to use the y-intercept and the slope because that info is given.

the y -int is when x = 0 and then y would equal -1/2. (0,-1/2)

then the slope is 3/4 which is rise over run so go three up (rise) and 4 across (run). make sure that your line has a positive slope ( / ) because the slope is positive in the equation, not negative ( \ )

You now have 2 points. Draw a line connecting the two points.

andreev551 [17]3 years ago

4 0

Use the site called Desmos, it's a graphing calculator and should help you in all the ways you need. It isn't complex. Just put that equation in a box and it graphs it for you.

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12 x 4 + 36 ÷ 4 - 37

Anika [276]

The answer is 20 you do multiplication first then the division, add what both the numbers that you got. Then subtract 37 and you get 20

4 0

3 years ago

If 45.78 ÷ 1.7 is written in long division form as long division set up where 17 is on the outside of the division symbol and 45

saveliy_v [14]

Answer:

The decimal point should be placed after the 0 in 45780.

Step-by-step explanation:

3 0

2 years ago

Find an expression which represents the difference when (9x−6) is subtracted from (6x+7) in simplest terms.

evablogger [386]

Answer:

3x + 1

Step-by-step explanation:

9x -6 -6x +7

9x-6x -6 +7

3x +1

8 0

2 years ago

HELPPPPOPPPOPPÑPPÑÑÑ

matrenka [14]

A.

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4 0

2 years ago

solmaris [256]

Answer:

The initial mass of the sample was 16 mg.

The mass after 5 weeks will be about 0.0372 mg.

Step-by-step explanation:

We can write an exponential function to model the situation.

Let the initial amount be A. The standard exponential function is given by:

$P(t)=A(r)^t$

Where r is the rate of growth/decay.

Since the half-life of Palladium-100 is four days, r = 1/2. We will also substitute t/4 for t to to represent one cycle every four days. Therefore:

$\displaystyle P(t)=A\Big(\frac{1}{2}\Big)^{t/4}$

After 12 days, a sample of Palladium-100 has been reduced to a mass of two milligrams.

Therefore, when x = 12, P(x) = 2. By substitution:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^{12/4}$

Solve for A. Simplify:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^3$

Simplify:

$\displaystyle 2=A\Big(\frac{1}{8}\Big)$

Thus, the initial mass of the sample was:

$A=16\text{ mg}$

5 weeks is equivalent to 35 days. Therefore, we can find P(35):

$\displaystyle P(35)=16\Big(\frac{1}{2}\Big)^{35/4}\approx0.0372\text{ mg}$

About 0.0372 mg will be left of the original 16 mg sample after 5 weeks.

5 0

3 years ago