Step-by-step explanation:
V= π*r²*h
V/π = r²*h
v/(π*r²) = h
= 5
x+y = 15
x = 15-y
Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes
It’s casey. when compared to other fractions, it stands supreme.
Step-by-step explanation:
7(36-2c+4)
=252 - 14c + 28
=310 - 14c