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Sauron [17]
3 years ago
12

Margin works in a factory. She receives a salary of $12 per hour and piecework pay for 12 cent per unit produced. Last week she

worked 38 hours and produced 755 units
a.What was her piecework pay?
b.What was her total hourly pay for the week?
c.What was her total pay for the week?
d.What would her total weekly salary have been if she produced 0 units?
Mathematics
1 answer:
Ann [662]3 years ago
4 0

Answer:

a: $90.60

B: $456.00

C: $546.60

Step-by-step explanation:

Wage: $12/hour Piecework: 12c/unit

Worked: 38 hours Made: 755 units

A: piecework pay

755(.12) = 90.6

B: hourly pay for the week

38(12) = 456

C: total pay

90.6+456=546.6

Hope this helps

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Alex777 [14]

Applying the midpoint formula, the coordinates of the other endpoint are: (-9, -13).

<h3>How to Apply the Midpoint Formula?</h3>

The midpoint formula, which can be used in determining the coordinates of the midpoint between two endpoints is usually expressed as: M[(x1 + x2)/2, (y1 + y2)/2].

Given the following coordinates:

Midpoint of GH --> m(-13/2,-6) = (x, y)

One endpoint ---> G(-4, 1) = (x1, y1)

The other endpoint ---> (x2, y2)

Plug in the values into the formula used in calculating the midpoint:

m(-13/2,-6) = [(-4 + x2)/2, (1 + y2)/2]

Solve for x2

-13/2 = (-4 + x2)/2

-13/2 × 2 = -4 + x2

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-9 = x2

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Solve for y2

-6 = (1 + y2)/2

2(-6) = 1 + y2

-12 = 1 + y2

-12 - 1 = y2

-13 = y2

y2 = -13

Thus, using the midpoint formula, the coordinates of the other endpoint are: (-9, -13).

Learn more about the midpoint formula on:

brainly.com/question/13115533

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Draw or write to explain why i hundred 4 ten and 14 tens name the same amount
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ten tens are one hundred and then they both have 4 tens or forty
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Please please help me
Gekata [30.6K]

Answer:

\large\boxed{\dfrac{\boxed{8}}{81}}

Step-by-step explanation:

\text{If}\ a_1,\ a_2,\ a_3,\ a_4,\ ...,\ a_n\ \text{is the geometric sequence, then}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...=\dfrac{a_n}{a_{n-1}}=constant=r-\text{common ration}.\\\\\text{We have}\ \dfrac{1}{2},\ \dfrac{1}{3},\ \dfrac{2}{9},\ \dfrac{4}{27},\ ...\\\\\dfrac{\frac{1}{3}}{\frac{1}{2}}=\dfrac{1}{3}\cdot\dfrac{2}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{2}{9}}{\frac{1}{3}}=\dfrac{2}{9}\cdot\dfrac{3}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{4}{27}}{\frac{2}{9}}=\dfrac{4}{27}\cdot\dfrac{9}{2}=\dfrac{2}{3}

\bold{CORRECT}\\\\\dfrac{x}{\frac{4}{27}}=\dfrac{2}{3}\qquad\text{multiply both sides by}\ \dfrac{4}{27}\\\\x=\dfrac{2}{3}\cdot\dfrac{4}{27}\\\\x=\dfrac{8}{81}

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What is the midpoint of the segment below?
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Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me​
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Answer:

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Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

                   = - cos60cosx - sin60sinx

                   = - \frac{1}{2} cosx - \frac{\sqrt{3} }{2} sinx

squaring to obtain cos² (120 + x)

= \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

                   = -cos60cosx + sin60sinx

                   = - \frac{1}{2}cosx + \frac{\sqrt{3} }{2}sinx

squaring to obtain cos²(120 - x)

= \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

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Putting it all together

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= cos²x + \frac{1}{2}cos²x + \frac{3}{2}sin²x

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= \frac{3}{2}(cos²x + sin²x) = \frac{3}{2}

                 

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