no it cant. irrational number is any real number that cannot be expressed as a ratio.
Answer:
The 75th term of the arithmetic sequence -17, -13, -9.... is:
![a_{75}=279](https://tex.z-dn.net/?f=a_%7B75%7D%3D279)
Step-by-step explanation:
Given the sequence
![-17, -13, -9....](https://tex.z-dn.net/?f=-17%2C%20-13%2C%20-9....)
An arithmetic sequence has a constant difference 'd' and is defined by
computing the differences of all the adjacent terms
The difference between all the adjacent terms is the same and equal to
![d=4](https://tex.z-dn.net/?f=d%3D4)
The first element of the sequence is:
![a_1=-17](https://tex.z-dn.net/?f=a_1%3D-17)
now substitute
and
in the nth term of the sequence
![a_n=a_1+\left(n-1\right)d](https://tex.z-dn.net/?f=a_n%3Da_1%2B%5Cleft%28n-1%5Cright%29d)
![a_n=4\left(n-1\right)-17](https://tex.z-dn.net/?f=a_n%3D4%5Cleft%28n-1%5Cright%29-17)
![a_n=4n-21](https://tex.z-dn.net/?f=a_n%3D4n-21)
Now, substitute n = 75 in the
sequence to determine the 75th sequence
![a_n=4n-21](https://tex.z-dn.net/?f=a_n%3D4n-21)
![a_{75}=4\left(75\right)-21](https://tex.z-dn.net/?f=a_%7B75%7D%3D4%5Cleft%2875%5Cright%29-21)
![a_{75}=300-21](https://tex.z-dn.net/?f=a_%7B75%7D%3D300-21)
![a_{75}=279](https://tex.z-dn.net/?f=a_%7B75%7D%3D279)
Therefore, the 75th term of the arithmetic sequence -17, -13, -9.... is:
![a_{75}=279](https://tex.z-dn.net/?f=a_%7B75%7D%3D279)
Multiply the denominator by the whole number and add the numerator.
so it's
11÷-11= -1
Answer:
70.01 so 70
Step-by-step explanation:
Answer:
y = ![\frac{96}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B96%7D%7B5%7D)
Step-by-step explanation:
given that y and x are proportional then the equation relating them is
y = kx ← k is the constant of proportionality
to find k use the given condition y = 12 when x = 5
k =
= ![\frac{12}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B5%7D)
y =
x ← equation of proportionality
when x = 8, then
y =
× 8 = ![\frac{96}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B96%7D%7B5%7D)