Answer:
463833
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Medium
Solution
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In △ABD and △ACD, we have
DB=DC ∣ Given
∠ADB=∠ADC ∣ since AD⊥BC
AD=AD ∣ Common
∴ by SAS criterion of congruence, we have.
△ABD≅△ACD
⇒AB=AC ∣ Since corresponding parts of congruent triangles are equal
Hence, △ ABC is isosceles.
Answer:
A. (2+4)² +(5-8)²
Step-by-step explanation:
To find then distance between two points, we will follow the steps below;
write down the formula
D = √(x₂-x₁)²+(y₂-y₁)²
(-4, 8)
x₁=-4
y₁ = 8
(2,5)
x₂=2
y₂=5
we can now proceed to insert the values into the formula
D = √(x₂-x₁)²+(y₂-y₁)²
= √(2+4)²+(5-8)²
=√(6)² + (-3)²
=√36+9
=√45
Therefore the expression which gives the distance between two the two points is (2+4)² +(5-8)²
Answer:
the answer is -7
Step-by-step explanation:
hope this helps
Answer:
SSS postulate because three sides of a triangle are are congruent
