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erik
[133]
2 years ago
11
Find four consecutive integers such that the sum of the first and third is eight les than twice the sum of the second and fourth
Mathematics
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answer:
lyudmila
[28]
2 years ago
5
0
X, x+1, x+2, x+3 are 4 consecutive integers
2(x + x+2) = 5(x+3) - 26
2(2x+2) = 5(x+3) - 26
4x + 4 = 5x + 15 - 26
4x + 4 = 5x - 11
15 = x
15, 16, 17, 18
x, x+2, x+4 consecutive even integers
2(x+4)+11 = x + 9
2x + 8 + 11 = x + 9
2x + 19 = x + 9
x = -10
-10, -8, -6
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