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erik [133]
3 years ago
11

Find four consecutive integers such that the sum of the first and third is eight les than twice the sum of the second and fourth

Mathematics
1 answer:
lyudmila [28]3 years ago
5 0
X, x+1, x+2, x+3 are 4 consecutive integers

2(x + x+2) = 5(x+3) - 26
2(2x+2) = 5(x+3) - 26
4x + 4 = 5x + 15 - 26
4x + 4 = 5x - 11
15 = x
15, 16, 17, 18

x, x+2, x+4 consecutive even integers
2(x+4)+11 = x + 9
2x + 8 + 11 = x + 9
2x + 19 = x + 9
x = -10
-10, -8, -6
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HACTEHA [7]

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Show me how to solve this, please.<br> <img src="https://tex.z-dn.net/?f=%282.7%20%2A%2010%5E%7B5%7D%20%29%20%2F%20%289%20%2A%20
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Answer:

3 * 10 ^-2

Step-by-step explanation:

When we divide numbers in scientific notation first divide the number portion

2.7 /9 =.3

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H(y)=4|y+2|−3, evaluate h(−8).
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21

7 0
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Who can Help me please...
lesantik [10]

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