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3 years ago

What is the first step in simplifying the expression below?

Mathematics

1 answer:

zlopas [31]3 years ago

6 0

Answer:

subtracting 1 from 3 is the correct answer of this question

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Alex Ar [27]

$\bf \cfrac{3x}{x^2-3x-10}-\cfrac{6x}{x^2-7x+10}\implies \cfrac{3x}{(x-5)(x+2)}-\cfrac{6x}{(x-5)(x-2)}
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\textit{our LCD is clearly then }(x-5)(x+2)(x-2)
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\cfrac{(x-2)3x~~-~~[(x+2)6x]}{(x-5)(x+2)(x-2)}\implies \cfrac{3x^2-6x~~-~~[6x^2+12x]}{(x-5)(x+2)(x-2)}
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\cfrac{3x^2-6x-6x^2-12x}{(x-5)(x+2)(x-2)}\implies \cfrac{-3x^2-18x}{(x-5)(x+2)(x-2)}$

4 0

3 years ago

Question 2 of 10

artcher [175]

Answer:

Step-by-step explanation:

8 0

2 years ago

The midpoint of UV is (5, -10). The coordinates of one endpoint are U(3,6). Find the coordinates of endpoint V.

Grace [21]

The answer is (7, -26) for The second endpoint.

We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.

(Ux + Vx)/2 = Mx

(Vx + 3)/2 = 5

Vx + 3 = 10

Vx = 7

And now we do the same thing for y values

(Uy + Vy)/2 = My

(Vy + 6)/2 = -10

Vy + 6 = -20

Vy = -26

This gives us the final point of (7, -26)

6 0

2 years ago

Read 2 more answers

What is the equation of the line?

BartSMP [9]

B. it’s the change in y over the change in x

7 0

2 years ago

Michmoo Computer Company sells computers and computer parts by mail. The company assures its customers that products are mailed

Anastaziya [24]

Answer: (60.858, 69.142)

Step-by-step explanation:

The formula to find the confidence interval for mean :

$\overline{x}\pm z_c\dfrac{\sigma}{\sqrt{n}}$ , where $\overline{x}$ is the sample mean , $\sigma$ is the population standard deviation , n is the sample size and $z_c$ is the two-tailed test value for z.

Let x represents the time taken to mail products for all orders received at the office of this company.

As per given , we have

Confidence level : 95%

n= 62

sample mean : $\overline{x}=65$ hours

Population standard deviation : $\sigma=18$ hours

z-value for 93% confidence interval: $z_c=1.8119$ [using z-value table]

Now, 93% confidence the mean time taken to mail products for all orders received at the office of this company :-

$65\pm (1.8119)\dfrac{18}{\sqrt{62}}\\\\ 65\pm4.142\\\\=(65-4.142,\ 65+4.142)\\\\= (60.858,\ 69.142)$

Thus , 93% confidence the mean time taken to mail products for all orders received at the office of this company : (60.858, 69.142)

8 0

3 years ago