After "26 years" the amount in A2 become greater than that in A1.
According to the question,
The future value of funds in A1:
= 
here, n = Number of years
The future value of A2 will be:
= ![\frac{10000}{0.08}[1.08^n-1]](https://tex.z-dn.net/?f=%5Cfrac%7B10000%7D%7B0.08%7D%5B1.08%5En-1%5D)
= ![125000[1.08^n-1]](https://tex.z-dn.net/?f=125000%5B1.08%5En-1%5D)
now,
→ ![125000[1.08^n -1] > 100000(1.08)^n](https://tex.z-dn.net/?f=125000%5B1.08%5En%20-1%5D%20%3E%20100000%281.08%29%5En)
→ 
→ 
By taking "log", we get
→
or,
(n "Number of years")
Each year, with $7000 in A2
→ ![\frac{7000}{0.08} [1.08^n -1]> 100000(1.08^n)](https://tex.z-dn.net/?f=%5Cfrac%7B7000%7D%7B0.08%7D%20%5B1.08%5En%20-1%5D%3E%20100000%281.08%5En%29)
→ 
→ 
By taking "log", we get
→
or,
(n "Number of years")
Learn more:
brainly.com/question/15175948