Find the X- and y-intercept of the line. 2x + 3y = -18

Mathematics

2 answers:

svetlana [45]3 years ago

6 0

Answer:

x-intercept = -9

y-intercept = -6

Step-by-step explanation:

The equation is

=> 2x+3y = -18

Finding x-intercept

Let's assume y = 0

The equation becomes

=> 2x = -18

Dividing both sides by 2

=> x = -9

Finding y-intercept:

Let's assume x = 0

The equation becomes

=> 3y = -18

Dividing both sides by 3

=> y = -6

Bad White [126]3 years ago

3 0

Answer: x = -9, y = -6

y = mx + b

2x + 3y = -18

Assuming x = 0

2(0) + 3y = -18

y = -6

Assuming y = 0

2x + 3(0) = -18

x = -9

You might be interested in

Identify the excluded values of this product. Then rewrite the product in simplest form.

lara [203]

$\frac{6 {y}^{2} + 18y - 60 }{3 {y}^{2} - 12y } \times \frac{ {y}^{2} - 16 }{ {y}^{2} + 2y - 8} \\ \\ \frac{ {6y + 30y - 12y - 60}^{2} }{3y(y - 4)} \times \frac{ {(y)}^{2} - ( {4)}^{2} }{ {y}^{2} + 4y - 2y - 8 } \\ \\ \frac{6y(y + 5) - 12(y + 5)}{3y(y - 4)} \times \frac{(y + 4)(y - 4)}{y(y + 4) - 2(y + 4)} \\ \\ \frac{(6y - 12)(y + 5)}{3y(y - 4)} \times \frac{(y + 4)(y - 4)}{(y + 4)(y - 2)} \\ \\ \frac{6(y - 2)(y + 5)}{3y(y - 2)} \\ \\ \frac{2(y + 5)}{y} .$