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2 years ago

WILL MARK BRAINLIEST PLEASE HELP

Mathematics

1 answer:

Softa [21]2 years ago

5 0

Answer:

$3 \: years \\ 30000 \times 0.97 \times 0.97 \times 0.97 = 27380.19 \\ 2 \: year \\ 30000 \times 0.97 \times 0.97 = 28227 \\ 1\: year \\ 30000 \times 0.97 = 29100$

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A box is placed on the floor.

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2 years ago

Ernesto Montenegro purchase a twelve 1000 Bonds having a quoted price of 100.75 he have to pay a 6% brokerage fee of the same pr

LenKa [72]

Answer: $106.8

Step-by-step explanation:

Given that the bond price is $100.75

With a 6% brokerage fee

Find the total cost to the nearest cent

First, we calculate the 6% brokerage fee= 6/100 × 100.75

= 0.06 x 100.75

= 6.045

Total cost therefore is the sum of brokerage fee and the cost of bond

= $6.045 + $100.75

= $106.795

To the nearest cent = $106.8

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2 years ago

What is the value of x in the triangles to the right?<br> A. 9<br> B. 12<br> C. 15<br> D. 17.5

Gnom [1K]

The answer for this is B

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2 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

2 years ago

What would be the exact side length of a square with the area of 8 m2

Paraphin [41]

Answer:

2*square root of 2

Step-by-step explanation:

The square root of 8 is equal to 2*square root of 2

5 0

2 years ago