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2 years ago

I need help so bad please help me out

Mathematics

1 answer:

Grace [21]2 years ago

7 0

I can’t see your upload like at all

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What are the next 4 terms to this sequence 2, 6, -4, 10, -14,

Kay [80]

Answer:

24, -38, 62, -100

Step-by-step explanation:

The recursive formula is a_n = a_(n-2) - a_(n-1)

so. we try this 4 times after the -14 term

a_3 = -4 = 2 - 6 = a_1 - a_2

...

a_6 = a_4 - a_5 = 10 - (-14) = 24

a_7 = a_5 - a_6 = -14 - (24) = -38

a_8 = a_6 - a_7 = 24 - (-38) = 62

a_9 = a_7 - a_8 = -38 - 62 = -100

a_10 = a_8 - a_9 = 62 - (-100) = 162

6 0

3 years ago

Solve the simultaneous equation, 2p - 3q = 4 3p + 2q = 9

Kobotan [32]

Answer:

p = $\frac{35}{13}$ and q = $\frac{6}{13}$

Step-by-step explanation:

Given equations:

2p - 3q = 4 -----------(i)

3p + 2q = 9 ------------(ii)

Let's solve this equation simultaneously using the elimination method

(a) Multiply equation (i) by 3 and equation (ii) by 2 as follows;

[2p - 3q = 4] x 3

[3p + 2q = 9] x 2

6p - 9q = 12 -------------(iii)

6p + 4q = 18 -------------(iv)

(b) Next, subtract equation (iv) from equation (iii) as follows;

[6p - 9q = 12]

- [6p + 4q = 18]

-13q = -6 -----------------(v)

(c) Next, make q subject of the formula in equation (v)

q = $\frac{6}{13}$

(d) Now substitute the value of q = $\frac{6}{13}$ into equation (i) as follows;

2p - 3( $\frac{6}{13}$ ) = 4

(e) Now, solve for p in d above

Multiply through by 13;

26p - 18 = 52

Collect like terms

26p = 52 + 18

26p = 70

Divide both sides by 2

13p = 35

p = $\frac{35}{13}$

Therefore, p = $\frac{35}{13}$ and q = $\frac{6}{13}$

8 0

2 years ago

Translate this phrase into an algebraic expression.

PSYCHO15rus [73]

Answer:

2m+8

Step-by-step explanation:

5 0

2 years ago

I have a whole packet :(

Maslowich

12 A . my guess would be to divide 2175 by 18 which would give you 120.83

7 0

3 years ago

A safety regulation states that the maximum angle of elevation for a rescue ladder is 72°. A fire department's longest ladder is

Julli [10]

Answer:

The maximum safe rescue height is 104.6 feet above the height of the ground.

Step-by-step explanation:

Consider a triangle ABC where C is the point where the rescue ladder is standing and AB be the building and Ladder making an angle of 72° as shown.

We have to find the height of the building.

Let x be the height of building

Using Trigonometric ratio,

$\sin C=\frac{\text{Perpendicular}}{\text{Hypotenuse}}$

$\sin 72^{\circ}=\frac{AB}{BC}$

$\sin 72^{\circ}=\frac{x}{110}$

$x=110 \times \sin 72^{\circ}$

$x=104.6$

So, the maximum safe rescue height is 104.6 feet above the height of

the ground.

5 0

3 years ago

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