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kirill115 [55]
3 years ago
13

A variety of energy bar regularly sells for $1.35, but for one week they were on sale for $0.95.

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
8 0

Answer:

E.1.05

Step-by-step explanation:

because you'll need to ad a dozen by thats number

actually I don't really know I feel ot would be E tho

TiliK225 [7]3 years ago
3 0

Answer:

E) $1.05

Step-by-step explanation:

before sale: $1.35×12=$16.20

during sale: $0.95×(12×3)=$34.20

total money spent=$16.20+$34.20=$50.40

total bars bought=12+(12×3)=48

average=

\frac{50.40}{48}  = 1.05

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Mr. Voelz estimates that he will spend $10 on concessions at the basketball game. He actually spends $15. What is the percent er
irina [24]

Answer:

I am not sure but if you divide those 2 numbers such as dividing 10 by 15 you will get 0.666666666667 but if you round it you will have 67%

Step-by-step explanation:

Plz mark Brainliest

5 0
3 years ago
Twenty six equals eight plus v
Mumz [18]

18. You can do this in a calculator. 26 - 8 = 18. v = 18.

6 0
3 years ago
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20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an
STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

n(A)=14

n(B)=11

n(A\cup B)=20

We know that,

n(A\cup B)=n(A)+n(B)-n(A\cap B)

20=14+11-n(A\cap B)

20=25-n(A\cap B)

Subtract both sides by 25.

20-25=-n(A\cap B)

-5=-n(A\cap B)

5=n(A\cap B)

We need to find the number of people who have a school certificate only, i.e. n(A\cap B').

n(A\cap B')=n(A)-n(A\cap B)

n(A\cap B')=14-5

n(A\cap B')=9

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3 0
3 years ago
Please help a girl outtttt
jeyben [28]

Answer:

bottom of graph will move from (0,0) to point (1,3) after transformation

Step-by-step explanation:

given

original : f(x) = x^{2}

transformed; g(x) = (x-1)^{2} + 3

look at this way g(x) =  (x-h)^{2} + k

if (x-h), h>0, move h units to the right

if k>0, move k units up

the bottom of the graph will be at point (1,3)

3 0
3 years ago
F(x)3x+5/x what is f(a+2)
Natalija [7]
F(X) = (3x + 5)/X
F(a + 2) = (3(a + 2) + 5)/(a + 2)
F(a + 2) = (3a + 6 + 5)/(a+2)
F(a + 2) = (3a + 11)/(a + 2).

This would be the final solution.
4 0
3 years ago
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