A tree is 14 meters tall. What is its height in feet? Use the following conversion: 1 meter is 3.3 feet

what is 0 + 0? I NEED HELP PLS RN RN IM GETTING GRADED ON THIS PLS HELP WILL MARK BRAINLIEST PLS HELP

kicyunya [14]

It's 00000000000000000000000

6 0

3 years ago

Two sets of 4 consecutive positive integers have exactly one integer in common. The sum of the integers in the set with greater

soldi70 [24.7K]

If you have two sets of integers {1, 2, 3, 4} and {4, 5, 6, 7}, then the sum of each set is 10 and 22, respectively, with a difference of 12. Based on logic, we know that this applies to any numbers you choose that meet the criteria. Number theory offers a more formalized outlook on these concepts.

The answer is D.

8 0

3 years ago

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a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$