Consider the line y=5/7x+7. Find the equation of the line that is parallel to this line and passes through the point (-5,-2). Fi
nd the equation of the line that is perpendicular to this line and passes through the point (-5,-2).
1 answer:
Step-by-step explanation:
m=5/7
m1=m2=5/7
L;y-(-2)=5/7(x-(-5)
y+2=5/7(x+5)
7y+14=5X+25
7y-5x=11 is parallel lines
m1*m2=-1 is perpendicular lines
m2=-1*7/5
m2=-7/5
L;y+2=-7/5(x+5)
5Y+10=-7x-35
5y+7x=-45 is perpendicular lines
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