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3 years ago

What is the curved surface area of a cylinder with radius = 14 cm and height = 6 cm? (Take π = 22/7)

Mathematics

1 answer:

Papessa [141]3 years ago

4 0

Answer:

528 cm²

Step-by-step explanation:

curved surface area of cylinder= $2\pi rh$ , where h is the height of the cylinder and r is the radius of the base.

Given that the radius is 14cm, r= 14.

Curved surface area of cylinder

$= 2( \frac{22}{7} )(14)(6) \\ = 528 \: cm^{2}$

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3x + 4y = -23

Stolb23 [73]

Answer:

the answer is -3/4 because if you use step by step explanation y= mx+b slope intercept form means y=mx+b use also implicit differentiation

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Find the area of the triangle with the given vertices. Use the fact that the area of the triangle having u and v as adjacent sid

Gnom [1K]

Answer:

The area of the triangle is $A=\sqrt{\frac{4027}{2}}$

Step-by-step explanation:

Using the fact that the area of the triangle having u and v as adjacent sides is given by

$A=\frac{1}{2}||{\bf u} \times {\bf v} ||$

We know that we want to take a cross product to compute the area of the triangle, but we need to be careful because it doesn't make sense if we take the cross product of points.

The first step is to build some vectors that describe this triangle.

According with the graph we can build the vectors:

${\bf AB}$ and ${\bf AC}$

The vector ${\bf AB}$ is the difference of point B minus point A

${\bf AB}=(5-3,5-5,0-9)=(2,0,-9)$

and the vector ${\bf AC}$ is the difference of point C minus point A

${\bf AC}=(-4-3,0-5,2-9)=(-7,-5,-7)$

Next we need to find the cross product of this vectors.

${\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}$

This is the definition of cross product of two vectors in space:

Let ${\bf u} = u_1{\bf i}+u_2{\bf j}+u_3{\bf k}$ and ${\bf v} = v_1{\bf i}+v_2{\bf j}+v_3{\bf k}$ be vectors in space. The cross product of ${\bf u}$ and ${\bf v}$ is the vector

${\bf u} \times {\bf v}=(u_2v_3-u_3v_2){\bf i}-(u_1v_3-u_3v_1){\bf j}+(u_1v_2-u_2v_1){\bf k}$

Applying this definition we get

${\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}$

$\begin{pmatrix}0\cdot \left(-7\right)-\left(-9\left(-5\right)\right)&-9\left(-7\right)-2\left(-7\right)&2\left(-5\right)-0\cdot \left(-7\right)\end{pmatrix}\\\\\begin{pmatrix}-45&77&-10\end{pmatrix}$

$||{\bf AB} \times {\bf AC}||=\sqrt{(-45)^2+(77)^2+(-10)^2} \\\\||{\bf AB} \times {\bf AC}||=\sqrt{2025+5929+100}\\\\||{\bf AB} \times {\bf AC}||=\sqrt{8054}$

The area of the triangle is

$A=\frac{1}{2}||{\bf AB} \times {\bf AC} ||=\frac{1}{2}\sqrt{8054}=\sqrt{\frac{4027}{2}}$

7 0

4 years ago

Who is responsible for developing the punnett square

AysviL [449]

Reginald Punnett and William Bateson were among the first English geneticists. Punnett devised the "Punnett Square" to depict the number and variety of genetic combinations, and had a role in shaping the Hardy-Weinberg law. Punnett and Bateson co-discovered "coupling" or gene linkage.

Mark brainliest please

Hope this helps you

7 0

3 years ago

A tree on a hillside casts a shadow c = 220 ft down the hill. if the angle of inclination of the hillside is b = 15° to the hori

MAXImum [283]

The height of the tree is 45ft

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3 years ago

For a closed For a closed rectangular box, with a square base x by x cm and height h cm, find the dimensions giving the minimum

12345 [234]

Answer:

x = h = ∛7 cm ≈ 1.913 cm

Step-by-step explanation:

The volume and other dimensions are related by ...

V = Bh = x²h

Solving for h gives ...

h = V/(x²)

The surface area is ...

S = 2(x² +h(2x)) = 2x² +4x(V/(x²)) = 2x² +4V/x

Differentiating with respect to x, we can find where the derivative is zero.

S' = 4x -4v/(x²) = 0

x³ -V = 0 . . . . . . . multiply by x²/4

x = ∛V . . . . . . . . . solve for x

h = V/(∛V)² = (∛V)³/(∛V)² = ∛V

The surface area is minimized when the box is a cube. Its edge lengths are all (∛7) cm ≈ 1.913 cm.

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3 years ago