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3 years ago

NEED HELP it’s a test please some one

Mathematics

1 answer:

Bezzdna [24]3 years ago

8 0

Answer:

1. The correct answer is B. N

3. The answer is C.) Associative Property of Addition

Step-by-step explanation:

1. Since $- \frac{\sqrt{64} }{2} = -4$ , then it means that -4 cannot be a natural number (N). By definition, natural numbers ( N ) are counting numbers that are positive integers.

3. According to the Associative Property of Addition:

(a + b ) + c = a + (b + c )

This definition matches your test question, "(7a * 2b) + 3c = 3c + (7a * 2b)"

Hope this explanation helps :)

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Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26

LiRa [457]

we know that

A polynomial in the form $a^{3}-b^{3}$ is called adifference of cubes. Both terms must be a perfect cubes

Let's verify each case to determine the solution to the problem

case A) $9w^{33} -y^{12}$

we know that

$9=3^{2}$ ------> the term is not a perfect cube

$w^{33}=(w^{11})^{3}$ ------> the term is a perfect cube

$y^{12}=(y^{4})^{3}$ ------> the term is a perfect cube

therefore

The expression $9w^{33} -y^{12}$ is not a difference of cubes because the term $9$ is not a perfect cube

case B) $18p^{15} -q^{21}$

we know that

$18=2*3^{2}$ ------> the term is not a perfect cube

$p^{15}=(p^{5})^{3}$ ------> the term is a perfect cube

$q^{21}=(q^{7})^{3}$ ------> the term is a perfect cube

therefore

The expression $18p^{15} -q^{21}$ is not a difference of cubes because the term $18$ is not a perfect cube

case C) $36a^{22} -b^{16}$

we know that

$36=2^{2}*3^{2}$ ------> the term is not a perfect cube

$a^{22}$ ------> the term is not a perfect cube

$b^{16}$ ------> the term is not a perfect cube

therefore

The expression $36a^{22} -b^{16}$ is not a difference of cubes because all terms are not perfect cubes

case D) $64c^{15} -a^{26}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$a^{26}$ ------> the term is not a perfect cube

therefore

The expression $64c^{15} -a^{26}$ is not a difference of cubes because the term $a^{26}$ is not a perfect cube

I'm adding a new case so I can better explain the problem

case E) $64c^{15} -d^{27}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$d^{27}=(d^{9})^{3}$ ------> the term is a perfect cube

Substitute

$64c^{15} -d^{27}=((2^{2})(c^{5}))^{3}-(d^{9})^{3}$

therefore

The expression $64c^{15} -d^{27}$ is a difference of cubes because all terms are perfect cubes

5 0

3 years ago

Read 2 more answers

Molly's snowboard is 150 cm long; Pete's is 16% longer. How long is Pete's snowboard?

Amiraneli [1.4K]

Answer:

174 centimeters

Step-by-step explanation:

You take 150 and divide it by 10 which gives you 15. since you divide it by 10 and it gives you 15 that means ten percent is 15 centimeters. since we need to find out what the 16 percent is we take the 15 and divide that by 10 which gives us 1.5. That tells us every 1 percent, is 1.5 centimeters. you take the 150 and add 15 and that gives you 165. We have already done 10 percent out of the 16 percent . Now we have to figure out how much the rest of the 6 percent is so we take the 1.5 and multiply it with the 6 and we get a 9. That covers up for the rest of the 6 percent out of the 16 percent. Now we add 165 with 9 to get our answer of 174 centimeters.

4 0

3 years ago

yarga [219]

Question

3/5 of students at a school are boys. If there are 2420 students at the school, how many are girls?

Answer:

<h2>968 girls</h2>

Step-by-step explanation:

if 3/5 are boys 2/5 are girls (5 - 3/5 = 2/5)

so 2420 * 2/5 = 968 girls

4 0

3 years ago

Read 2 more answers

Determine the

AlladinOne [14]

Answer:

a₄ = - $\frac{27}{2}$

Step-by-step explanation:

In a geometric sequence, the common ratio r is calculated as

r = $\frac{a_{2} }{a_{1} }$ = $\frac{a_{3} }{a_{2} }$ , substitute values

$\frac{2x+2}{x}$ = $\frac{3x+3}{2x+2}$ ( cross- multiply )

(2x + 2)² = x(3x + 3) ← expand both sides

4x² + 8x + 4 = 3x² + 3x ( subtract 3x² + 3x from both sides )

x² + 5x + 4 = 0 ← in standard form

(x + 1)(x + 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

x + 4 = 0 ⇒ x = - 4

However x ≠ - 1 as this would make the denominator of the second term equal to zero and therefore undefined.

Thus x = - 4 and

r = $\frac{2(-4)+2}{-4}$ = $\frac{-8+2}{-4}$ = $\frac{-6}{-4}$ = $\frac{3}{2}$

Then

a₁ = - 4

a₂ = - 4 × $\frac{3}{2}$ = - 6

a₃ = - 6 × $\frac{3}{2}$ = - 9

a₄ = - 9 × $\frac{3}{2}$ = - $\frac{27}{2}$

7 0

3 years ago

What is the function of a chemical equation

Savatey [412]

A chemical equation is the symbolic representation of a chemical reaction in the form of symbols and formulae, wherein the reactant entities are given on the left-hand side and the product entities on the right-hand side

Step-by-step explanation:

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3 years ago