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Leno4ka [110]
3 years ago
15

Question 10

Mathematics
1 answer:
wolverine [178]3 years ago
8 0

Answer:

b

Step-by-step explanation:

dfszvdsvsdrfesccvxdfesfes

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Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(3,−2), B(6, -2), C(6, 5) D
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Answer:

Step-by-step explanation:

Distance=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}} \\

A(3,-2) ;  B(6,-2)

AB=\sqrt{(6-3)^{2}+(-2-[-2])^{2}}\\\\ =\sqrt{3^{2}+(-2+2)^{2}}\\\\=\sqrt{9+0}=\sqrt{9}\\\\

AB = 3 units

B(6,-2) ;  C(6,5)

BC=\sqrt{(6-6)^{2}+(5-[-2])^{2}} \\\\=\sqrt{0+(5+2)^{2}}\\\\=\sqrt{(7)^{2}}\\

BC = 7 units

Area of rectangle = length * width

                             = AB * BC

                             = 3 * 7

                             = 21 square units

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There is only one positive integer which is exactly twice the sum of its digits. find this 2 digit number

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