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2 years ago

Study the figure. What is the measure of the missing exterior angle?

Mathematics

2 answers:

vlada-n [284]2 years ago

5 0

A u suck

Step-by-step explanation:

Gennadij [26K]2 years ago

4 0

Answer:

can't see any figure to study

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goblinko [34]

Answer:

$\displaystyle m=\frac{-1}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Reading a Cartesian plane
Coordinates (x, y)
Slope Formula: $\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point (4, 1)

Point (0, 3)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute in points [Slope Formula]: $\displaystyle m=\frac{3-1}{0-4}$
[Fraction] Subtract: $\displaystyle m=\frac{2}{-4}$
[Fraction] Simplify: $\displaystyle m=\frac{-1}{2}$

4 0

2 years ago

The length of the sides of a triangle are 2x +y/2, 5x/3+y + ½ and 2/3x +2y +5/2. If the triangle is equilateral, find its perime

Sav [38]

Answer:

Step-by-step explanation:

If the triangle is equilateral :

2x +y/2 = 5x/3+y + ½ = 2/3x +2y +5/2

so the perimeter is : P = 3(2x +y/2) or 3(5x/3+y + ½) or 3(2/3x +2y +5/2)

the simplest is : P = 3(2x +y/2)

P = 6x + (3y)/2

6 0

2 years ago

Find the value of x in the Parallelogram

andriy [413]

x=127 that is because a rectangle equals 365 degrees and two sides have to be parallel so 53+53=106 and 365-106=254 and 254/2=127

7 0

2 years ago

Let the function f(x) have the form fx) = Acos(x+C). To produce a graph that matches the one shown below, what must the value of

slava [35]

Answer:

B. 4

Step-by-step explanation:

The given function is of the form:

$f(x) = A \cos(x+C).$

A is called the amplitude of the given function.

We can read from the graph that, the function ranges between:

-4 and 4

This implies that:

$|A| = 4$

Therefore the amplitude of the function is 4.

Hence the value of A must be 4.

8 0

3 years ago

The end points of one diagonal of a rhombus are (-5,2) and (1,6). If the coordinates of the 3rd vertexare (-6,10), what are the

ad-work [718]

Look at the picture.

$E\left(\dfrac{-5+1}{2};\ \dfrac{2+6}{2}\right)\to E\left(\dfrac{-4}{2};\ \dfrac{8}{2}\right)\to E(-2;\ 4)$

$\vec{BE}=[-2-(-6);\ 4-10]=[4;\ -6]$

$D(x;\ y)\\\\\vec{ED}=[x-(-2);\ y-4]=[x+2;\ y-4]\\\\\vec{ED}=\vec{BE}\ therefore\\\\ \ [x+2;\ y-4]=[4;\ -6]\to x+2=4\ and\ y-4=-6\\\\x=2\ and\ y=-2\\\\Answer:\ \boxed{A.\ (2;\ -2)}$

8 0

2 years ago