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3 years ago

Y = (x-3)^2 when x = 9

Mathematics

2 answers:

hoa [83]3 years ago

4 0

l HOPE IT WILL HELP YOU.

Have a great day ahead.

Thank you.

^ - ^

Strike441 [17]3 years ago

3 0

Answer:

Step-by-step explanation:

9-3=6

6*6=36

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Good morning guys can you guys plz help on my math :D

Softa [21]

Answer:

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Question 2:

False

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Step-by-step explanation:

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5 0

3 years ago

Which quadratic equation has roots - 2 and 1/5 :

Sladkaya [172]

Answer:

$5 {x}^{2} \: + \: 8x \: - 2 \: = \: 0$

Step-by-step explanation:

$sum \: of roots = - 2 + \frac{1}{5} = - \frac{8}{5} \\ product \: of \: roots = - 2 \times \frac{1}{5} = - \frac{2}{5} \\ from \: general \: equation \\ a {x}^{2} + bx + c = 0 \\ {x}^{2} + \frac{8}{5} x \: - \frac{2}{5} = 0 \\ 5 {x}^{2} \: + \: 8x \: - 2 \: = \: 0$

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3 years ago

Please help me with this sum

mihalych1998 [28]

The answer is 1
6 -
6

8 0

4 years ago

PLEASE ANSWER FAST DUE IN 20 MINS PLEASE ANSWER FAST FAST FAST

BabaBlast [244]

Answer:

1 C

2 D and B

3 46

Step-by-step explanation:

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6 0

3 years ago

How many 'words' can be made from the name ESTABROK with no restrictions

Bumek [7]

The number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

<h3>How to determine the number of ways</h3>

Given the word:

ESTABROK

Then n = 8

p = 6

The formula for permutation without restrictions

P = n! ( n - p + 1)!

P = 8! ( 8 - 6 + 1) !

P = 8! (8 - 7)!

P = 8! (1)!

P = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 × 1

P = 40, 320 ways

Thus, the number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

Learn more about permutation here:

brainly.com/question/4658834

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6 0

2 years ago