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mixer [17]
3 years ago
13

When a number * is divided by 22, the quotient is 74 and the remainder is 0. What will be the quotient when * is divided by 11?

Mathematics
2 answers:
cricket20 [7]3 years ago
4 0

Answer:

The quotient will be 2 this is the answer

vesna_86 [32]3 years ago
3 0

Answer:

148

Step-by-step explanation:

Let the required number be x.

Since,

Dividend = Divisor*Quotient + Remainder

So,

x = 22*74 + 0

x = 1628

Thus, the required number is 1628

Now, let us divide 1628 by 11

1628 \div 11 = 148

Hence, the quotient will be 148.

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Determine whether the value is a discrete random​ variable, continuous random​ variable, or not a random variable. a. The number
Bumek [7]

Answer:

a. Discrete

b. Discrete

c. Not a random variable

d. Continuous

e. Discrete

f. Continuous

Step-by-step explanation:

The discrete random variable is countable while continuous random variable is measurable.

a. The number of fish caught is a discrete random variable because these are countable.

b. The number of text book authors are also countable so it is a discrete random variable.

c. The political party affiliation of adults is not a random variable because the political party affiliation depends on person's interest and it cannot be randomly assigned to person. Also random variable is the numerical outcome of random experiment whereas political affiliation is the categorical variable that results in non numerical responses such as Democrat, Republicans etc.

d. The square footage of a house is measurable and so it is a continuous random variable.    

e. The number of free dash throw attempts are countable so it is a discrete random variable

f. The weight of Upper T dash bone steak is measurable and so it is a continuous random variable.

5 0
3 years ago
Michelle ordered 200 t shirts to sell at the school carnival. She paid $2.80 per shirt, plus 5% of the total order for shipping.
kap26 [50]

Answer:

12.75 dollars

Step-by-step explanation:

5% = 2.94$

150% = 7$

2.80 + 5% + 150% = 12.75 for each t-shirt she sale

5 0
3 years ago
A scooter (small motorcycle) is bought at a price of $9,000. It loses 14% of its value very year. Express this scenario as a seq
IrinaK [193]

The scenario as a sequence recursively and explicitly is

a_{1} = 9,000 ;  a_{n} = 0.86 • a_{n-1}

a_{n}=9,000(0.86)^{n-1}

Step-by-step explanation:

The recursive formula for the nth term of a geometric sequence is

a_{1} = first term ;  a_{n} = r • a_{n-1} , where

  • a_{1} is the first term in the sequence
  • r is the common ratio  between the consecutive terms

The explicit formula for the nth term of a geometric sequence is

a_{n}=a(r)^{n-1} , where

  • a is the first term
  • r is the common ratio between the consecutive terms

∵ A scooter (small motorcycle) is bought at a price of $9,000

∵ It loses 14% of its value very year

- That means the new price of it will be 100% - 14% of the

  previous year

∵ 100% - 14% = 86%

∵ 86% = 86 ÷ 100 = 0.86

∴ Each year the price will be 0.86 of the price of the previous year

∴ The common ratio r = 0.86

∵ The initial price of the scooter is $9,000

∴ a_{1} = 9,000

∵ r = 0.86

- Substitute them in the the recursive formula

∴ a_{1} = 9,000 ;  a_{n} = 0.86 • a_{n-1}

∵ a = 9,000

∵ r = 0.86

- Substitute them in the the explicit formula

∴ a_{n}=9,000(0.86)^{n-1}

The scenario as a sequence recursively and explicitly is

a_{1} = 9,000 ;  a_{n} = 0.86 • a_{n-1}

a_{n}=9,000(0.86)^{n-1}

Learn more:

You can learn more about the sequences in brainly.com/question/1522572

#LearnwithBrainly

5 0
3 years ago
What is the value if m in the equation 1\2m-3/4n=16 when n=8
Papessa [141]
\frac{1}{2}m-\frac{3}{4}n=16\ \ \ \ \ \ \ \ \ \ \ \ n=8\\\\\frac{1}{2}m-\frac{3}{4}\cdot8=16\\\\\frac{1}{2}m-6=16\\\\\frac{1}{2}m=16+6\\\\\frac{1}{2}m=22\ \ \ \ \ \ \ \ |\cdot2\\\\m=44
6 0
3 years ago
Please Help!! These are 3 seperate questions I need help with.
Brums [2.3K]

Answer:

  1. A.  (x1, x2) = (1, 4)
  2. C.  There is no solution.
  3. B.  The solutions are of the form: (x1, x2, x3) = (4t+4, t-3, t)

Step-by-step explanation:

1.  Subtract the first equation from twice the second to eliminate x2.

  2(2x1 -x2) -(x1 -2x2) = 2(-2) -(-7)

  3x1 = 3 . . . . . simplify

  x1 = 1 . . . . . . .divide by 3

Substitute this value into the second equation.

  2·1 -x2 = -2

  4 -x2 = 0 . . . . . add 2

  4 = x2 . . . . . . . add x2

The solution is (x1, x2) = (1, 4).

__

2. Multiply the first equation by 3 and add the second equation.

  3(-5x1 -3x2) +(15x1 +9x2) = 3(7) +(2)

  0 = 23 . . . . . not true;

There is no solution.

__

3. There are two equations in 3 unknowns, so there cannot be a unique solution. The equations are not dependent, so there will be an infinite number of solutions that can be written in terms of a single parameter (t).

Let x3 = t. Then the system of equations can be rewritten as

  2x1 - 5x2 = 23 +3t

  x1 - 4x2 = 16

Subtracting twice the second equation from the first, we have ...

  (2x1 -5x2) -2(x1 -4x2) = (23 +3t) -2(16)

  3x2 = 3t -9 . . . simplify

  x2 = t -3 . . . . . divide by 3

Substituting this into the second equation above, we have ...

  x1 -4(t -3) = 16

  x1 = 16 +4t -12 . . . . . . add 4(t-3)

  x1 = 4t +4 . . . . . . . . simplify

The solutions are (x1, x2, x3) = (4t+4, t-3, t).

_____

The attachment shows the first system solved by graphical means. This validates our answer.

7 0
3 years ago
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