Answer:
The answer is 3x^2-x-6. Hope it helps you ❤️
Answer:
I can't help sorry you can adjust your selg
A) f(-4)-f(-5)=-3- (-11)=-3+11=8
f(-2)-f(-3)=13-5= 8
f(0)-f(-1)=29-21= 8
f(2)-f(1)=45-37=8
f(3)-f(2)=53-45=8
all are 8
b) f(-3)-f(-5)= 5- (-11)= 5+11=16
f(-2)-f(-4)=13-(-3)=13+3=16
f(1)- f(-1)=37-21= 16
f(3)-f(1)=53-37=16
c) f(-2)-f(-5)=13-(-11)=13+11=24
f(-1)-f(-4)=21-(-3)=21+3=24
f(0)-f(-3)=29-5=24
f(1)-f(-2)=37-13=24
f(2)-f(-1)=45-21=24
d) The differences have the same ratio.
cause is a linear function f(x)=ax+b
f(x+3)-f(x)=a(x+3)+b-ax-b=ax+3a-ax=3a
f(x+2)-f(x)=2a
f(x+1)-f(x)=a
so it is the same for every x
Answer:
2x²+5![\sqrt{x+2}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B2%7D)
Step-by-step explanation:
Answer:
Distance =√(x₁ - y₁)²+ (x₂ - y₂)² = √97 = 9.85
Step-by-step explanation:
The Matrix X and Y could also be referred to as vectors in Rⁿ dimensions.
if Vector X = ( x₁ , x₂) and Vector Y = (y₁ , y₂)
then, Distance (X-Y) = ||X-Y|| = √(x₁ - y₁)²+ (x₂ - y₂)²
where, x₁ = 8, x₂ = -5 and y₁ = -1 , y₂ = -9
Distance = √(8 - (-1))²+ (-5 - (-9))² = √9² + 4² =√97 = 9.85