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Andru [333]
3 years ago
12

Give the values of n and ell for an electron in a 4d orbital. n = ell = 16 select the values of mell and ms that are possible fo

r an electron in a 4d orbital. mell = −4 −3 −2 −1 −1/2 0 +1/2 1 2 3 4 ms = −4 −3 −2 −1 −1/2 0 +1/2 1 2 3 4
Mathematics
1 answer:
Anestetic [448]3 years ago
8 0
There are four quantum numbers: n, l, ml and ms. When the orbital is 4d, the 4 is corresponding to n. Thus, n=4. Then, the d corresponds to l = 2. Now, to find the value for ml, take the values of -l to +l. Therefore,

<em>ml = -2, -1, 0, 1, 2</em>

<em>Then,ms could only be either +1 or -1.</em>
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How many percents are added every 6 minutes ?
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Answer:try using google and some other help full information it works for me

Step-by-step explanation:

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PLEASE HELP
Tems11 [23]

QUESTION A

The given multiplication problem is

\frac{39}{64} \times \frac{8}{13}

Factor each term to obtain;

\frac{13\times 3}{8\times8} \times \frac{8}{13}

Cancel out the common factors to obtain;

\frac{1\times 3}{8\times1} \times \frac{1}{1}

Simplify to get;

\frac{3}{8}

QUESTION B

The given multiplication problem is

\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}

This the same as

\frac{2\times 1\times 4}{3\times 5\times 7}

This simplifies to;

\frac{8}{105}

QUESTION C

The given problem is

\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}

This is the same as

\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}

=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}

This simplifies to

=\frac{1}{4}

QUESTION D.

The given expression is

\frac{4}{9}\times 54

Factor the 54 to obtain;

\frac{4}{9}\times 9\times 6

Cancel the common factors to get;

\frac{4}{1}\times 1\times 6

This simplifies to;

=24

QUESTION E

The given problem is

20\times 3\frac{1}{5}

Convert the mixed numbers to improper fraction to obtain;

=20\times \frac{16}{5}

=4\times5 \times \frac{16}{5}

Cancel the common factors to get;

=4\times1 \times \frac{16}{1}

=64

QUESTION F

The multiplication problem is

11 \times 2 \frac{7}{11}

Convert the mixed numbers to improper fractions to obtain;

11 \times \frac{29}{11}

Cancel out the common factors to get;

=1 \times \frac{29}{1}

Simplify;

=29

QUESTION G

The given problem is

5\frac{1}{3}\times 5\frac{1}{8}

Convert to improper fractions;

=\frac{16}{3}\times \frac{41}{8}

Cancel out the common factors to get;

=\frac{2}{3}\times \frac{41}{1}

=\frac{82}{3}

Convert back to mixed numbers

=27\frac{1}{3}

QUESTION H

The given expression is

10\frac{2}{3} \times 1\frac{3}{8}

Convert to improper fraction to get;

\frac{32}{3} \times \frac{11}{8}

Cancel common factors to get;

=\frac{4}{3} \times \frac{11}{1}

Simplify

=\frac{44}{3}

Convert back to mixed numbers;

=14\frac{2}{3}

7 0
3 years ago
The vertices of angleABC are A(1,1) B(5,1) C(3,3) drawl the triangle and it’s image A’B’C’ reflected in the Y axis. What are the
nevsk [136]

For any point reflected in the y- axis

(x, y ) → (- x, y )

A(1, 1) → A'(- 1, 1)

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Nastasia [14]
The interior angles of a triangle need to be equal to 180°, so to solve this you need to figure out how many degrees you need to get 180°.

46 + 61 = 107

180 - 107 = 73

The measure of the third angle is B. 73°.
5 0
3 years ago
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