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stiv31 [10]
3 years ago
14

Linda ran 2 mile in 1/3 hour. How many miles did she run in one hour?

Mathematics
2 answers:
Debora [2.8K]3 years ago
6 0

Answer:

6

Step-by-step explanation:

if she runs 2 miles in 1/3 of an hour, all you have to do is multiply 2 by 3 and you get 6.

Semenov [28]3 years ago
4 0
She would’ve ran 6 miles in an hour.
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In d Mohit deposited 2 12000 be depos would ( money 900. The interest B 800 o O 1800​
jeka57 [31]

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5 0
2 years ago
Pam and her sister have a pattern of saving money. Pam saved 40 dollars and her brother saved 100 dollars.
Keith_Richards [23]

Answer:

true

Step-by-step explanation:

Pam saved 40

her bro saves 100

let us take this as ration 40 is to 100 which can also be written in fractional for like 40/100 now we simplify it how by dividing both by 20 so (40/20)/(100/20) which will give 2/5 which can be written as 2 is to 5 so this is true

8 0
3 years ago
Read 2 more answers
Find the greatest common factor and the least common multiple of 16 and 20. The prime factorizations of each number are given.
kykrilka [37]

Answer:

GCF 4, LCM 80

Step-by-step explanation:

Since both 16 and 20 have two 2s as factor, their greatest common factor is 4.

The LCM is found by multiplying all of the remaining factors by the LCM:

16 still has (2 x 2), 20 still has (5), times the GCF (4)  so 2 x 2 x 5 x 4 = 80.

5 0
2 years ago
Please solve for x and show work
Ksju [112]

Answer:

18 \times 14 =  {(6x)}^{2}  \\  {x}^{2}  =  \frac{18 \times 14}{36}  = 7 \\ x =  \sqrt{7}

4 0
3 years ago
If the sum of the first 12 terms of a geometric series is 8190 and the common ratio is 2. Find the first term and the 20th term.
Reil [10]

The first term is 2 and the 20th term is 1048576 .

<u>Step-by-step explanation:</u>

Here we have , If the sum of the first 12 terms of a geometric series is 8190 and the common ratio is 2. We need to Find the first term and the 20th term. Let's find out:

We know that Sum of a GP is :

⇒ S_n = \frac{a(r^n-1)}{r-1}

So ,Sum of first 12 terms is :

⇒ S_1_2 = \frac{a(2^{12}-1)}{2-1}

⇒ 8190=a(2^{12}-1)

⇒ \frac{8190}{4095}=a

⇒ a=2

Now , nth term of a GP is

⇒ a_n = ar^{n-1}

So , 20th term is :

⇒ a_2_0 = 2(2)^{20-1}

⇒ a_2_0 = (2)^{20}

⇒ a_2_0 = 1048576

Therefore , the first term is 2 and the 20th term is 1048576 .

8 0
3 years ago
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