Question

4(kr - 8)+5k^2r=6k=9show work

Answer 1

Answer:

4(k*r - 8) + 5k^2

= 4(9 * 6 - 8) + 5 * 9^2

= 4(54 - 8) + 5 * 81

= 4(46) + 405

= 184 + 405

= 589.

Coding the problem:

In[7]:= 4 (k*r - 8) + 5 k^2 /. {r -> 6, k -> 9}

Out[7]= 589

Answer 2

Answer:

$589$

Step-by-step explanation:

$4(kr-8)+5k^{2}$

$r=6$

$k=9$

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$4\left(\left(9\right)\left(6\right)-8\right)+5\left(9\right)^2$

⇒ Multiply 9 and 6 = 54

$4(54-8)+5\times 9^{2}$

⇒ Subtract 8 from 54 = 46

$4\times 46+5\times9^{2}$

⇒ Multiply 4 and 46 = 184

$184+5\times 9^{2}$

⇒ Calculate 9 to the power of 2= 81

$184+5\times 81$

⇒ Multiply 5 and 81 = 405

$184+405$

⇒ Add

$589$

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