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sukhopar [10]
3 years ago
9

4(kr - 8)+5k^2r=6k=9show work

Mathematics
2 answers:
4vir4ik [10]3 years ago
6 0

Answer:

4(k*r - 8) + 5k^2

= 4(9 * 6 - 8) + 5 * 9^2

= 4(54 - 8) + 5 * 81

= 4(46) + 405

= 184 + 405

= 589.

Coding the problem:

In[7]:= 4 (k*r - 8) + 5 k^2 /. {r -> 6, k -> 9}

Out[7]= 589

astra-53 [7]3 years ago
6 0

Answer:

589

Step-by-step explanation:

4(kr-8)+5k^{2}

r=6

k=9

<u>----------------------------</u>

<u />4\left(\left(9\right)\left(6\right)-8\right)+5\left(9\right)^2

<u>⇒ Multiply 9 and 6 = 54</u>

4(54-8)+5\times 9^{2}

<u>⇒ Subtract 8 from 54 = 46</u>

4\times 46+5\times9^{2}

<u>⇒ Multiply 4 and 46 = 184</u>

184+5\times 9^{2}

<u>⇒ Calculate 9 to the power of 2= 81</u>

184+5\times 81

<u>⇒ Multiply 5 and 81 = 405</u>

184+405

<u>⇒ Add</u>

589

<u>------------------------</u>

<u>OAmalOHopeO</u>

<u>------------------------</u>

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