All categories

3 years ago

Pleaseeee help its due noww

Mathematics

2 answers:

son4ous [18]3 years ago

4 0

Answer:

option no c) 10/3

Step-by-step explanation:

hope it is useful

kolezko [41]3 years ago

3 0

Answer:

second one is correct answer

You might be interested in

What is #5 I don’t know the answer.

denpristay [2]

If the axis of symmetry is x=-1, the vertex will have x-coordinate -1.

The point (0, 5) cannot be the vertex. The friend is not correct.

_____

If the point (1, 5) is on the graph so is the image of that point when it is reflected across the axis of symmetry. That image point is (-3, 5). A parabola that goes through points (1, 5) and (-3, 5) will not go through point (0, 5).

4 0

3 years ago

Round to the nearest ones place for the problem as follows......3.9

WINSTONCH [101]

I believe it would be 4.

5 0

3 years ago

Read 2 more answers

Please help maths homework

kaheart [24]

Answer:

1). -4

2). -12

Step-by-step explanation:

Because algebra

8 0

3 years ago

Help needed plaese✌

monitta

5x-3=2.5x+x solve this equation that I just gave you for X then plug it in to 2.5x and that will equal MN

7 0

4 years ago

What Val are restricted from the domain of

djverab [1.8K]

<u>Given</u>:

The given expression is $\frac{\left(4 x^{2}-4 x+1\right)}{(2 x-1)^{2}}$

We need to determine the values for which the domain is restricted.

<u>Restricted values:</u>

Let us determine the values restricted from the domain.

To determine the restricted values from the domain, let us set the denominator the function not equal to zero.

Thus, we have;

$(2x-1)^2\neq 0$

Taking square root on both sides, we get;

$2x-1\neq 0$

$2x\neq 1$

$x\neq \frac{1}{2}$

Thus, the restricted value from the domain is $x\neq \frac{1}{2}$

Hence, Option A is the correct answer.

7 0

4 years ago