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algol13
3 years ago
9

What is the least common multiple of 19 and 38?

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0
38. 19 + 19= 38. 38 + 0= 38
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What is the equation of the line that passes through the point (-5,1) and has a slope of -1/5?
olchik [2.2K]

Answer:

x + 5y = 0

Step-by-step explanation:

y = mx + b

y = -1/5 x + b

1 = -1/5 (-5) + b

1 = 1 + b

b = 0

y = -1/5 x

5y = -x

x + 5y = 0

4 0
3 years ago
Find the difference in simplest form. <br> 2b/b^2-2b+1 - 2/b^2-2b+1
kolezko [41]
1) factor the denominators: 2b/(b-1)2 - 2/ (b-1)2
2) MAKE SURE YOU HAVE A COMMON DENOMINATOR
3) combine the numerators: 2b-2/(b-1)2
4) distribute 2 from numerator: 2(b-1)/(b-1)2
5) simplify; answer is 2/(b-1)

7 0
3 years ago
1/3 (12 - 24v) = -2(4v -2)
ANEK [815]
Opening brackets gives;
4-8v=-8v+4
Putting like terms together;
4-4=-8v+8v
0=0
There is no solution thus.
3 0
3 years ago
This question is from the similarity chapter. It would be really kind of you if you would answer this question.
katen-ka-za [31]

Answer:

a) 1650 m

b) 1677.05 m

Step-by-step explanation:

Hi there!

<u>1) Determine what is required for the answers</u>

For part A, we're asked for solve for the horizontal distance in which the road will rise 300 m. In other words, we're solving for the distance from point A to point C, point C being the third vertex of the triangle.

For part B, we're asked to solve for the length of the road, or the length of AB.

<u>2) Prove similarity</u>

In the diagram, we can see that there are two similar triangles: Triangle AXY and ABC (please refer to the image attached).

How do we know they're similar?

  1. Angles AYX and ACB are corresponding and they both measure 90 degrees
  2. Both triangles share angle A

Therefore, the two triangles are similar because of AA~ (angle-angle similarity).

<u>3) Solve for part A</u>

Recall that we need to find the length of AC.

First, set up a proportion. XY corresponds to BC and AY corresponds to AC:

\frac{XY}{BC}=\frac{AY}{AC}

Plug in known values

\frac{2}{300}=\frac{11}{AC}

Cross-multiply

2AC=11*300\\2AC=3300\\AC=1650

Therefore, the road will rise 300 m over a horizontal distance of 1650 m.

<u>4) Solve for part B</u>

To find the length of AB, we can use the Pythagorean theorem:

a^2+b^2=c^2 where c is the hypotenuse of a right triangle and a and b are the other sides

Plug in 300 and 1650 as the legs (we are solving for the longest side)

300^2+1650^2=c^2\\300^2+1650^2=c^2\\2812500=c^2\\1677.05=c

Therefore, the length of the road is approximately 1677.05 m.

I hope this helps!

3 0
3 years ago
A dose of a new pharmaceutical drug is decaying according to the half-life model f(t) = Ne-0.2174, where N is the dose
Rudiy27

Answer:

  14.7

Step-by-step explanation:

Perhaps your equation is ...

  f(t) = N·e^(-0.2174t)

We want f(6) = 4, so ...

  4 = N·e^(-0.2174·6) = N·e^-1.3044 ≈ 0.2713N

  N = 4/0.2713 = 14.7 . . . . milligrams

The dose amount was about 14.7 mg.

6 0
3 years ago
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