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hram777 [196]
3 years ago
11

24. ABCDE and PQRST are regular pentagons.

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
3 0

Answer:

126°

Step-by-step explanation:

In quadrilateral DSRC, SR || DC (given)

AP = BQ = CR = DS = ET (given)

\therefore CR bisects \angle DCB

\therefore m\angle DCR=\frac{108\degree}{2}

(108\degree is the measure of an angle of pentagon)

\therefore m\angle DCR=54\degree

\because m\angle DCR + m\angle SRC=180\degree

(Measure of interior angles on the same side of transversal)

\therefore 54\degree + m\angle SRC=180\degree

\therefore  m\angle SRC=180\degree- 54\degree

\therefore  m\angle SRC=126\degree

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