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muminat
3 years ago
9

Let f be the function given by f(x)=2x^3−4x^2−5. What is the value of f′(−1) ?

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
7 0

f'(x) = 6x^2-8x

f'(-1) = 6(-1)^2 -8(-1)

      = 6 +8

      = 14

Ivahew [28]3 years ago
7 0

Answer:

f'(-1)=14

Step-by-step explanation:

you have to graph it first and then calculate when x=-1 for the prime

hope this helps (btw, prime means the opposite integer, example, a(x)=1, a'(x)=-1)

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One number is 2 more than another. The difference between their squares is 24.
kkurt [141]

Answer: The numbers are 7 and 5

Step-by-step explanation:

Let the first number be x and the second number be y.

From the first statement , it was said that one of the number is two more than the other , that is

x - y = 2  .................. equation 1

square of x is x^{2} and the square of y is y^{2} , the difference between thier squares implies

x^{2} - y^{2} = 24 .............. equation 2

solving the resulting simultaneous equations by substitution method:

From equation 1 , make x the subject of the formula , that is

x = 2 + y ............. equation 3

substitute equation 3 into equation 2 , we have

(2+y)^{2} - y^{2} = 24

Expanding , we have

y^{2} + 4y + 4 - y^{2}  = 24

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Subtract 4 from both sides

4y = 20

y = 20/4

y = 5

substitute y = 5 into equation 3 , we have

x = 5+ 2

x = 7

Therefor the numbers are 7 and 5

7 0
3 years ago
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