2 years ago

Let f be the function given by f(x)=2x^3−4x^2−5. What is the value of f′(−1) ?

Mathematics

2 answers:

Cerrena [4.2K]2 years ago

7 0

f'(x) = 6x^2-8x

f'(-1) = 6(-1)^2 -8(-1)

= 6 +8

= 14

Ivahew [28]2 years ago

7 0

Answer:

f'(-1)=14

Step-by-step explanation:

you have to graph it first and then calculate when x=-1 for the prime

hope this helps (btw, prime means the opposite integer, example, a(x)=1, a'(x)=-1)

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