A puppy and a kitten are 180 meters apart when they see each other. The puppy can run at a speed of 25 m/sec, while the kitten c
an run at a speed of 20 m/sec.
How soon will they meet if they simultaneously start running towards each other?
2 answers:
Answer: 36 sec
Step-by-step explanation:
Let
x------> distance the kitten runs before being caught by the puppy
Remember that
The speed is equal to divide the distance by the time
v=d/t
solve for t
t=d/v
so
equate the time
x/20=(180+x)/25
25x=20(180+x)
25x=3,600+20x
25x-20x=3,600
x=3,600/5=720 m
t=d/v=720/20=36 sec
or
t=(720+180)/25=900/25=36 sec
Answer:
Step-by-step explanation:
we are starting with formula S=D/T; S= speed; D=distance; T=time
T= D/25 for puppy
T=(180-D)/20 for kitten
we are having 2 equations!
180 - D=20*T and D<u>=25*T</u> => 180-25*T=20*T =>180= 45*T => T=180/45
T=4 SEC
T=D/25=>D=4*25=100 METERS
SO THEY WILL MEET AFTER 4 SECONDS IF THEY SIMULTANEOUSLY START RUNNING TOWARD EACH OTHER!
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