1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
insens350 [35]
4 years ago
15

A puppy and a kitten are 180 meters apart when they see each other. The puppy can run at a speed of 25 m/sec, while the kitten c

an run at a speed of 20 m/sec.
How soon will they meet if they simultaneously start running towards each other?
Mathematics
2 answers:
ser-zykov [4K]4 years ago
6 0

Answer: 36 sec

Step-by-step explanation:

Let

x------> distance the kitten runs before being caught by the puppy

Remember that

The speed is equal to divide the distance by the time

v=d/t

solve for t

t=d/v

so

equate the time

x/20=(180+x)/25

25x=20(180+x)

25x=3,600+20x

25x-20x=3,600

x=3,600/5=720 m

t=d/v=720/20=36 sec

or

t=(720+180)/25=900/25=36 sec

Vlad [161]4 years ago
4 0

Answer:

Step-by-step explanation:

we are starting with formula S=D/T; S= speed; D=distance; T=time

T= D/25 for puppy

T=(180-D)/20 for kitten

we are having 2 equations!

180 - D=20*T   and D<u>=25*T</u>   =>  180-25*T=20*T =>180= 45*T => T=180/45

T=4 SEC

T=D/25=>D=4*25=100 METERS

SO THEY WILL MEET AFTER 4 SECONDS IF THEY SIMULTANEOUSLY START RUNNING TOWARD EACH OTHER!

You might be interested in
I need help ASAP im very confused on the box part I put the two on the top but then what else?​
r-ruslan [8.4K]

Answer is in the file below

tinyurl.com/wpazsebu

8 0
3 years ago
Read 2 more answers
Mr. Dunford will give 6 pencils to each of his 30 students in his class. There are 12 pencils in each box he will order. He has
horsena [70]

Answer:

The answer to this problem is 4

Step-by-step explanation:

6 0
3 years ago
Write a quadratic equation with integer coefficients and the given numbers as solutions.
adoni [48]

Answer:

1.)  f(x) = x*x - 7x + 10

2.) f(x) = x*x - 5x

3.) f(x) = 4*x*x - 5x - 6

4.) f(x) = 6*x*x -5x + 1

Step-by-step explanation:

1.)  2 and 5     (x -2)(x - 5) = f(x)  =  x*x - 7x + 10

2.)  0 and 5     f(x) = x*(x -5) =  x*x - 5x

3.) -3/4  and 2     (x + 3/4)(x -2) = x*x - (5/4) x - 3/2,

 need integers   f(x) = 4xx - 5x - 6

4.) 1/2  and 1/3    (x - 1/2)(x - 1/3) = f(x)

 x*x  - 1/3 x  - 1/2 x +  1/6  

xx  -  5/6  x  + 1/6

6 xx - 5x  + 1

4 0
4 years ago
If 12 and 20 each divide K without a remainder, what is the value of K?
Juli2301 [7.4K]

Factors of 12 : 1, 2, 3, 4, 6, 12

Factors of 20: 1, 2, 4, 5, 10, 20

In both lists of factors, 4 is in common. Therefore, the value of K is 4 because it can divide into both 12 and 20 without a remainder. 2 is also another possible value of K.

4 0
4 years ago
Read 2 more answers
I need this quick please answer fast​
Sonja [21]

Answer:

the figures are congruent because they have 3 congruent sides and three congruent angles

4 0
4 years ago
Read 2 more answers
Other questions:
  • Please help I can't find these angle measures
    14·1 answer
  • What is the Least Common Multiple of x and 3x?
    12·2 answers
  • PLZ, I need help with this problem!
    10·1 answer
  • Please help!<br> What is g(f(4))=(g o f)(-2)=?<br> A.21<br> B.23<br> C.25<br> D.27
    6·1 answer
  • There are two pizzas. Conor ate 1⁄4 of a pizza, Brandon 2⁄8, Tyler 3⁄4, and Audrey 4⁄8. Who ate the most of the two pizzas? A. T
    11·1 answer
  • Can someone help me find AC​
    13·1 answer
  • I need an answer for 5/6x4. I appreciate the effort in helping. Sorry im not very good at fractions
    13·2 answers
  • The sum of two numbers is 52 and the difference is 8. What are the numbers?
    10·2 answers
  • Solving the systems of equations by elimination-solo team teach<br><br> x+y=-7 <br> 3x+y=-9
    8·1 answer
  • 485 <img src="https://tex.z-dn.net/?f=485%20divided%20by%209" id="TexFormula1" title="485 divided by 9" alt="485 divided by 9" a
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!