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Vedmedyk [2.9K]
3 years ago
14

SOMEONE HELP ME PLEASE

Mathematics
1 answer:
jenyasd209 [6]3 years ago
4 0

Answer: The median, because the data distribution is skewed to the left

EXPLANATION

Given the box plot with the following parameters: 

Minimum value at 11

First Quartile, Q1 at 22.5

Median at 34.5

Third Quartile, Q3 at 36

Maximum value at 37.5

First, we notice that the data distribution is skewed to the left because the median (34.5) is closer to the third quartile (36) than to the first quartile

(22.5).

Furthermore, we know that the mean provides a better description of the center when the data distribution is symmetrical while the median provides a better description of the center when the data distribution is skewed.

Therefore, we conclude that for the given box plot, the median will provide a better description of the center because the data distribution is skewed to the left.

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liberstina [14]

Answer:

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Step-by-step explanation:

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PolarNik [594]

Answer:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

Step-by-step explanation:

<u>Trinomio Cuadrado Perfecto</u>

El producto notable llamado cuadrado de un binomio se expresa como:

(a-b)^2=a^2-2ab+b^2

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}

\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8

\displaystyle b=\frac{1}{7}mpz^4

Nos cercioramos de que el término central es 2ab:

\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4

Operando:

\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5

Una vez verificado, ahora podemos decir que:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

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Answer:

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Answer:

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Step-by-step explanation:

Let L = Mr.Lin's present age,

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First equation  is

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The second equation is  

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L + 3 = 3*((38-L)+3),   or

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4L = 120,

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