The answer to the equation 1/3(6x-15)= 1/2(10x-4) is D. -1
<em><u>ANSWER</u></em>
<em>Since </em><em>probably </em><em>part </em><em>of </em><em>the</em><em> </em><em>pie </em><em>was </em><em>already </em><em>eaten </em><em>therefore </em><em>we </em><em>find </em><em>the </em><em>fration </em><em>of </em><em>the </em><em>pie </em><em>in </em><em>the </em><em>beginning</em><em> </em><em>which </em><em>is</em>
<em>=</em><em> </em><em>1</em><em> </em>
<em>=</em><em> </em><em>5</em><em>/</em><em>5</em>
<em><u>Fraction </u></em><em><u>William </u></em><em><u>ate;</u></em>
<em>=</em><em> </em><em>3</em><em>/</em><em>4</em><em> </em><em> </em><em>of </em><em>1</em>
<em>=</em><em> </em><em>3</em><em>/</em><em>4</em><em> </em><em>of </em><em>5</em><em>/</em><em>5</em>
<em>=</em><em> </em><em>3</em><em>/</em><em>4</em><em> </em><em>×</em><em> </em><em>5</em><em>/</em><em>5</em>
<em>=</em><em> </em><em>3</em><em>/</em><em>4</em>
<em> </em>
<em><u>CONCLUSION</u></em>
A fraction is a part of a whole so no matter how the fraction would increase or decrease the part William ate will remain the same
3x³×y²×12x²×y×z=36x⁵×y³×z
Answer:
a. 1/2 + 9/10 = 5/10+9/10 = 14/10 = 7/5 = 1 2/5 meters or ribbon
b. 5/8 = 15/24, 7/12 = 14/24 Jeff jogged longer and by 1/24 kilometers
c. 3/9 = 6/18. 15/18-6/18 = 9/18 = 1/2 left.
Hope this helps :)
Step-by-step explanation:
recalling that d = rt, distance = rate * time.
we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?
so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.
then Wanda kicks in, rolling like a lightning at 16mph.
let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.
the distance both have travelled is the same "d" miles, reason why they "meet", same distance.
![\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blcccl%7D%20%26%5Cstackrel%7Bmiles%7D%7Bdistance%7D%26%5Cstackrel%7Bmph%7D%7Brate%7D%26%5Cstackrel%7Bhours%7D%7Btime%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20Hector%26d%2612%26t%2B%5Cfrac%7B3%7D%7B2%7D%5C%5C%5B1em%5D%20Wanda%26d%2616%26t%20%5Cend%7Barray%7D%5Cqquad%20%5Cimplies%20%5Cbegin%7Bcases%7D%20%5Cboxed%7Bd%7D%3D%2812%29%5Cleft%28%20t%2B%5Cfrac%7B3%7D%7B2%7D%20%5Cright%29%5C%5C%5B1em%5D%20d%3D%2816%29%28t%29%20%5Cend%7Bcases%7D)
