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Igoryamba
3 years ago
12

The histogram shown represents the funds (dollars) raised by a number of fundraisers in a community to help the poor. How many f

undraisers raised funds between $600 and $800? A. 17 B. 8 C. 9 D. 16
(Please explain your answer, also I need help asap!)

Mathematics
2 answers:
daser333 [38]3 years ago
8 0

Answer:

Option A is correct.

The Number of fundraisers that raised funds between $600 and $800 = 17

Step-by-step explanation:

The x-axis represents the amount of dollars raised by the fundraisers.

The y-axis represents the number of fundraisers that raise a corresponding particular amount of dollars.

So, the question asks to give how many fundraisers raised funds between $600 and $800.

From the graph attached, from $600 to $800 entail two bars; one from $600 to $700 and the other one from $700 to $800.

The corresponding frequency for the bar that raised $600 to $700 = 7

The corresponding frequency for the bar that raised $700 to $800 = 10

Total frequency of fundraisers that raised between $600 and $800 = 7 + 10 = 17

Hope this Helps!!!

lions [1.4K]3 years ago
4 0

Answer:

option A is correct that is 17.

Step-by-step explanation:

We have been given a histogram  which is showing y-axis represents  number of fundraisers and x-axis represents  funds

So, we need to find the number of fundraisers raised funds between $600 and $800

In $600- $800 funds interval  the number of fundraisers are 10+7 =17

So, option A is correct that is 17.

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Consider the following sample set of scores. Assume these scores are from a discrete distribution. 21 29 32 38 38 45 50 64 72 10
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Answer:

Original data: 21 29 32 38 38 45 50 64 72 100

\bar X = \frac{21+29+32+38+38+45+50+64+72+100}{10}=48.9

Mode =38.

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Step-by-step explanation:

Original data: 21 29 32 38 38 45 50 64 72 100

The mean is calculated with the following formula:

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And if we replace we got:

\bar X = \frac{21+29+32+38+38+45+50+64+72+100}{10}=48.9

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have an even number of points the median is calculated as the average between the observations 5 and 6 from the dataset ordered.

Median = \frac{38+45}{2}=41.5

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\bar X = \frac{\sum_{i=1}^{10} X_i}{10}

And if we replace we got:

\bar X = \frac{2+29+32+38+38+45+50+64+72+100}{10}=47

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have an even number of points the median is calculated as the average between the observations 5 and 6 from the dataset ordered.

Median = \frac{38+45}{2}=41.5

Change 2: 29 32 38 38 45 50 64 72 100

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And if we replace we got:

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