Question 12 of 30
1 answer:
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Answer:
Please find the punnet square to this question as an attachment
F1 generation:
genotype = BW
Phenotype = Erminette offsprings
F2 generation:
genotype = BB (1): BW(2): WW(1)
Phenotype = 1 Black, 2 Erminette, 1White
Explanation:
This question involves a gene coding for feather color in chickens. The allele for black feathers (B) is codominant with the allele for white feathers (W) to form an erminette chicken (black and white speckles).
According to this question, a cross between a chick with black (BB) feathers and chicken with white (WW) feathers will result in an all erminette chicken (BW) in the F1 generation (see attached image)
Also, in the F2 generation got by self-crossing the Erminette genotype in the F1 generation (BW), the following genotypic and phenotypic ratios are observed:
Genotypic ratio = BB (1): BW(2): WW(1)
Phenotypic ratio = 1 Black, 2 Erminette, 1White
Answer:
a) 1/16, b) 4/16, c) 1/16, d) 1/16, e) 4/16, f) 4/16, g) 0 + alleles, h) 1/256, i) 1 + alleles, j) 4/256, k) 2 + alleles, l) 16/256, m) 3 + alleles, n) 24/256, o) 4 + alleles), p) 36/256, q) 5 + alleles, r) 24/256, s) 6 + alleles, t) 16/256, u) 7 + alleles, v) 4/256, w) 8 + alleles, x) 1/256.
You will find the uncompleted Punnett square (missing in the problem statement) and the complete modified Punnett square in the attached files
Explanation:
Due to technical problems, you will find the complete explanation in the attached files
