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3 years ago

In operations how to solve 3x−33+5

Mathematics

1 answer:

REY [17]3 years ago

8 0

Answer:

-94

Step-by-step explanation:

First Step- multiply 3 and 33

Second Step-. Divide the anwser you got from 5

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Which of the following points satisfies the inequality x ≥ -3? (Select all that apply.) (0, -2) (5, -5) (-3, 4) (-4, 2)

Naddik [55]

Answer:

The correct answer is (0, -2) (5, -5) (-3, 4)

Step-by-step explanation:

The given inequality is x ≥ -3

<u>To find the correct answers</u>

1) (0, -2)

x ≥ -3

0 ≥ -3 TRUE

2) (5, -5)

x ≥ -3

0 ≥ -3 TRUE

3) (-3, 4)

x ≥ -3

0 ≥ -3 TRUE

4) (-4, -2)

x ≥ -3

5 ≥ -3 FALSE

Therefore the correct answer is (0, -2) (5, -5) (-3, 4)

7 0

3 years ago

Read 2 more answers

What is the area of 1 times 6/7?

Rzqust [24]

It's 6/7 because 1 times anything like 1x10 =10 so it 6/7

6 0

3 years ago

Read 2 more answers

Geometry . Cosines / sines. Find a and round to the nearest 10th

Lorico [155]

This is the good part of Trigonometry, actually measuring triangles. It's much better than all the identities around sine and cosine and the rest, which actually have more to do with circles than triangles.

This part of trig has a short menu:

Law of Cosines. Three ways to write it, one is $c^2 =a^2+b^2-2ab \cos C$

Law of Sines: $\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

Triangle angles: $A+B+C=180^\circ$

and two special cases of the Law of Cosines, the Pythagorean Theorem

$C=90^\circ, \quad \quad c^2=a^2+b^2$

and the Collinear Points Theorem:

$C=180^\circ, \quad \quad c^2=a^2+b^2 - 2 a b \cos 180^\circ = a^2+b^2+2ab=(a+b)^2$

$c = a+b$

Here we choose Triangle Angles followed by Law of Sines:

A = 180 - 105 -15 = 60 degrees

$\dfrac{a}{\sin 60^\circ}= \dfrac{2}{\sin 105^\circ}$

$a= \dfrac{2 \sin 60^\circ}{\sin 105^\circ} = 1.793...$

Answer: 1.8 cm

When I was a student we'd be expected to get $\sin 105^\circ$ exactly and get

$a = 3 \sqrt{2} - \sqrt 6$

But that was before online homework.

5 0

3 years ago

The square of a whole number is between 1200 and 1600. The number must be between

gladu [14]

1200 and 1600 iomnlnklk

6 0

3 years ago

Ten friends went out to dinner. two friends each paid $12 for dinner, three friends each paid $13 for dinner, and five friends e

NeX [460]

$12 + $12 + $13 + $13 + $13 + $17 + $17 + $17 + $17 + $17 = 148

148 ÷ 10 = 14.8

$14.80 is the median amount the ten friends had to pay.

7 0

3 years ago