Answer: The answer is (B) ∠SYD.
Step-by-step explanation: As mentioned in the question, two parallel lines PQ and RS are drawn in the attached figure. The transversal CD cut the lines PQ and RS at the points X and Y respectively.
We are given four angles, out of which one should be chosen which is congruent to ∠CXP.
The angles lying on opposite sides of the transversal and outside the two parallel lines are called alternate exterior angles.
For example, in the figure attached, ∠CXP, ∠SYD and ∠CXQ, ∠RYD are pairs of alternate exterior angles.
Now, the theorem of alternate exterior angles states that if the two lines are parallel having a transversal, then alternate exterior angles are congruent to each other.
Thus, we have
∠CXP ≅ ∠SYD.
So, option (B) is correct.
Answer:
D) (0, -3)
Step-by-step explanation:
The solution of two linear equations is the point of intersection of their graphs.
From the graph, the point of intersection of the graphs of the two linear equations is on the y-axis. So, the 
value on the 
axis is always 0. Also, the point is below the x-axis. So, the value of the point will be negative.
From the choices given, only (0,-3) matches the above conditions.
Therefore, the correct choice is D. (0, -3).
Answer:
Step-by-step explanation:
6x^2+4x-42
2(3x^2+2x-21)=0
3x^2+2x-21=0
3x^2+(9-7)x-21=0
3x^2+9x-7x-21=0
3x(X+3)-7(X+3)=0
(3X-7)(X+3)=0
So Answer is (3x-7)(X+3)
Answer:
10 units
Step-by-step explanation:
Given data
P = (3, 1) and Q = (-3, -7)
x1=3
y1=1
x2= -3
y2= -7
The expression for the distance between two coordinate is
d=√((x_2-x_1)²+(y_2-y_1)²)
Substitute
d=√((-3-3)²+(-7-1)²)
d=√((-6)²+(-8)²)
d=√36+64
d=√100
d=10 units
Hence the distance is 10 units
