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makvit [3.9K]
2 years ago
13

Whats 1-2x+3y for x=-2 and y=-5 ?​

Mathematics
1 answer:
lawyer [7]2 years ago
5 0

Answer:

-10

Step-by-step explanation:

2*-2=-4

3*-5=-15

1-(-4)+(-15)=-10

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Without using a calculator, determine the number of real zeros of the function
natta225 [31]
There should be a total of 3 zeros because the largest exponent is 3. 
8 0
2 years ago
Of 5
aniked [119]

Answer:

Krutika

Step-by-step explanation:

Lets convert each person's typing rate to words/min.

Krutika:

80 minutes = 6000 words

1 minute = (6000/80) words

              = 75 words

Typing Rate: 75 words / min

Mark:

60 minutes = 4200 words

1 minute = (4200/60) words

              = 70 words

Typing Rate: 70 words / min

David:

90 minutes = 5850 words

1 minute = (5850/90) words

              = 65 words

Typing Rate: 65 words / min

From the above, we can see Krutika has the fastest rate of words per minute.

3 0
1 year ago
"given a sum and a product, find two integers x and y, where x + y === sum,"
noname [10]
What’s the question?
8 0
3 years ago
In triangle , side and the perpendicular bisector of meet in point , and bisects . If and , what is the area of triangle
stich3 [128]

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, 145–√5  is the area of a triangle.

I supposed here that [ABD] is the perimeter of ▲ ABD.

As  BD  is a bisector of  ∠ABC ,

ABBC=ADDC=97

Let  ∠B=2α

Then in isosceles  △DBC

∠C=α

BC=2∗DC∗cosα=14cosα

Thus  AB=18cosα

The Sum of angles in  △ABC  is  π  so

∠A=π−3α

Let's look at  AC=AD+DC=16 :

AC=BCcosC+ABcosA

16=14cos2α+18cosαcos(π−3α)

[1]8=7cos2α−9cosαcos(3α)

cos(3α)=cos(α+2α)=cosαcos(2α)−sinαsin(2α)=cosα(2cos2α−1)−2cosαsin2α=cosα(4cos2α−3)

With  [1]

8=cos2α(7−9(4cos2α−3))

18cos4−17cos2α+4=0

cos2α={12,49}

First root lead to  α=π4  and  ∠BDC=π−∠DBC−∠C=π−2α=π2 . In such case  ∠A=π−∠ABD−∠ADB=π4, and  △ABD  is isosceles with  AD=BD. As  △DBC  is also isosceles with  BD=DC=7,  AD=7≠9.

Thus first root  cos2α=12  cannot be chosen and we have to stick with the second root  cos2α=49. This gives  cosα=23  and  sinα=5√3.

The area of a triangle ABD=12h∗AD  where h  is the distance from  B  to  AC.

h=BCsinC=14cosαsinα

Area of  triangle ABD=145–√5

= 145–√5.

Incomplete question please read below for the proper question.

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, what is the area of triangle ABD?

Learn more about the Area of the triangle at

brainly.com/question/23945265

#SPJ4

6 0
2 years ago
Help!!!!<br> Measure the angle and classify it as right, acute, or obtuse.<br> &lt;2
nalin [4]

Answer:

B. 25, acute

Step-by-step explanation:

It is acute because it is less than 90°

4 0
3 years ago
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