Answer:
Step-by-step explanation:
The position function is
and if we are looking for the time t it takes for the ball to hit the ground, we are looking for the height of the ball when it is on the ground. Of course the height of anything on the ground is 0, so if we set s(t) = 0 and solve for t, we will find our answer.
and factor that however you are currently factoring in class to get that
t = -.71428 seconds or
t = 1.42857 seconds (neither one of those is rational so they can't be expressed as fractions).
We all know that time will never be a negative value, so the time it takes this ball to hit the ground is
1.42857 seconds (round how you need to).
Answer:
![x^{2} +y^{2}=25](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2By%5E%7B2%7D%3D25)
![x^{2} +y^{2}=5](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2By%5E%7B2%7D%3D5)
<em>Radius: 5</em>
<em>Radius: </em>![\sqrt{5}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D)
Step-by-step explanation:
(see images below)
Hope this helped!
~<u>rere</u>
The question "What is the LCM and GCF of 36 and 81?" can be split into two questions: "What is the LCM of 36 and 81?" and "What is the GCF of 36 and 81?"
In the question "What is the LCM and GCF of 36 and 81?", LCM is the abbreviation of Least Common Multiple and GCF is the abbreviation of Greatest Common Factor.
To find the LCM, we first list the multiples of 36 and 81 and then we find the smallest multiple they have in common. To find the multiples of any number, you simply multiply the number by 1, then by 2, then by 3 and so on. Here is the beginning list of multiples of 36 and 81:
Multiples of 36: 36, 72, 108, 144, 180, 216, etc.
Multiples of 81: 81, 162, 243, 324, 405, 486, etc.
The least multiple on the two lists that they have in common is the LCM of 36 and 81. Therefore, the LCM of 36 and 81 is 324.
Answer:
there r no variables shown
Step-by-step explanation:
Answer:
4
Step-by-step explanation: