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Nat2105 [25]
4 years ago
14

Explain why you do not have to do any computing to solve 15 by 0 by (13+7)

Mathematics
1 answer:
NARA [144]4 years ago
6 0
We dont have to do any cmputing, because multiplying by 0 is always 0. Its mean that no matter what are the different numbers, if we multiply it by 0, we get 0

The result is 0
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This table shows some values of an exponential function.
ValentinkaMS [17]

Step-by-step explanation:

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What is the result when 212 is decreased by 28%
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3 years ago
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(-3,20) (3,0) (18,20) (13,18) is it a function
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3 years ago
Fairfield Homes is developing two parcels near Pigeon Fork, Tennessee. In order to test different advertising approaches, it use
evablogger [386]

Answer:

(1)  Null Hypothesis, H_0 : \mu_1 = \mu_2

    Alternate Hypothesis, H_1 : \mu_1\neq \mu_2

(2) Test statistics = -1.48

(3) At the 0.05 significance level, Fair field conclude that the population means are same.

Step-by-step explanation:

Let \mu_1 = mean annual family income for 12 people making inquiries at the first development

\mu_2 = mean annual family income for 24 people making inquiries at the second development

s_1 = standard deviation of annual family income for 12 people making inquiries at the first development

s_2 = standard deviation of annual family income for 24 people making inquiries at the second development

n_1 = sample of people of first development i.e. 12

n_2 = sample of people of second development i.e. 24

(1) Null Hypothesis, H_0 : \mu_1 = \mu_2  {population means are same}

  Alternate Hypothesis, H_1 : \mu_1\neq \mu_2  {population means are different}

<u>DECISION RULE ;</u>

  • If the test statistics is less than the critical value of t from table at 5% significance level, then we will accept null hypothesis, H_0 .
  • If the test statistics is more than the critical value of t from table at 5% significance level, then we will reject null hypothesis, H_0 .

(2) The test statistics is given by;

                      \frac{(X_1bar -X_2bar) - (\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } } ~ t_n__1+n_2-2

where,  X_1bar = Sample mean income of people at first development

                        = $153,000

X_2bar = Sample mean income of people at second development = $171,000  

s_1 = $42,000  and   s_2 = $30,000

   s_p= \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2}} =  \sqrt{\frac{(12-1)42000^{2}+(24-1)30000^{2}  }{12+24-2}} = 34344.30

Test statistics = \frac{(153000 -171000) - 0}{34344.30\sqrt{\frac{1}{12}+\frac{1}{24}  } } ~ t_3_4

                       = -1.48

(3) At 5% level of significance, t table gives critical value of 2.032 at 34 degree of freedom.Since our test statistics is less than the critical value of t so considering our decision rule, we will accept null hypothesis.

And conclude that population means are same.

4 0
4 years ago
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