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GuDViN [60]
3 years ago
14

Eleven members of the Middle School Math Club each paid the same amount for a guest speaker to talk about problem solving at the

ir math club meeting. They paid their guest speaker $1−A−2−. What is the missing digit A of this 3-digit number?
Mathematics
1 answer:
RSB [31]3 years ago
4 0
So what we know is that there is a number 1?2 that is divisible by 11.

what was 11 multiplied by to get this number?  it must start with "1" since 1*1=1 and end with "2" since 1*2=2 and there is 2 at the end of the product .

so let's try: what is 11*12? 132? yes, that sounds good!

so the missing number is 3 and they each paid 12 dollars.
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Analyze the diagram below and complete the instructions that follow.<br> 550<br> 450
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Answer:

130 degrees

Step-by-step explanation:

let the angle be x

2x+45+55=360(Sum of angles in quad)

2x=260

x=130

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If it takes Mr. Williams 1/5 hour to grade each of his students’ tests, how many tests can he grade in 4 hours?
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The equation g(120) = 4 can be interpreted to mean: "On Day 2, 120 seconds after the
Scilla [17]

Answer:

hole bola gola dhola sola

ur answer is c. g(t) = d

4 0
3 years ago
Two ants, red ant and black ant, creeping along lines in 3-space. At time t, red ant is at point on the line
mylen [45]
A. The distance between the red ant and the black ant is five units.

To represent the red ant,
xr = 3 - t 
yr = 2 + 2 t 
zr = 6 + 2 t 

To represent the black ant, 
xb = t/2 
yb = 2 + 3 t 
zb = 2 + t 

To calculate,
at t = 0 
xb - xr = -3 
yb - yr - 2-2 = 0 
zb - zr = 2-6 = -4 
Therefore,
d = √(9+16) = √(25) = 5

b. There will be no collision between the two ants.

To calculate,
3 - t = t/2
6 - 2t = t
6 = 3t
t = 2 

If t = 2,
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4 0
3 years ago
The average weight of 3 containers A,B and C is 3.2kg. Container A is twice as heavy as container B. Containers B is 400 g heavi
dlinn [17]

Answer:

The weight of container C is 2.1kg.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the weight of container A.

y is the weight of container B.

z is the weight of container C.

The average weight of 3 containers A,B and C is 3.2kg.

This means that the total weight is 3*3.2 = 9.6kg. So

x + y + z = 9.6

Container A is twice as heavy as container B.

This means that x = 2y.

Containers B is 400 g heavier than container C.

400g is 0.4kg. So

This means that y = z + 0.4, or z = y - 0.4

Replacing y and z as functions of x in the first equation:

x + y + z = 9.6

2y + y + y - 0.4 = 9.6

4y = 10

y = \frac{10}{4} = 2.5

Container C

z = y - 0.4 = 2.5 - 0.4 = 2.1

The weight of container C is 2.1kg.

4 0
3 years ago
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