Protein-protein interactions within the CARMA1-BCL10-MALT1 complex:
- The T-cell receptor and B-cell receptor-dependent NF-B induction and lymphocyte activation are mediated by the CBM complex, which is made up of the proteins CARMA1, BCL10, and MALT1.
- Each of the proto-oncoproteins CARMA1, BCL10, and MALT1 is a somatic gain-of-function mutation or chromosomal translocation, and dysregulation of CBM signaling is a characteristic of numerous lymphoid malignancies, including Activated B-cell Diffuse Large B-cell Lymphoma.
- Moreover, a number of immunological dysregulation diseases have been linked to both gain- and loss-of-function germline mutations in CBM complex proteins.
- Over the past ten years, careful examination of the interactions of CBM components has yielded a wealth of detailed structural knowledge.
- Here, we discuss important discoveries about the molecular nature of these protein-protein interactions that have helped the research develop a detailed understanding of how these proteins come together to form high-order filamentous CBM complexes.
- Approaches to therapeutic suppression of the CBM complex have thus far centered on obstructing MALT1 protease activity in order to treat lymphoid malignancy and/or autoimmunity.
- The structural effects of MALT1 protease inhibitors on significant protein-protein interactions are also reviewed in detail.
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Chromosome duplications and deletions frequently result in abnormal phenotypes or inviable gametes. Gene dosage is modified is a major contributor to this phenomenon.
In the field of genetics, we can define gene dosage as the quantitative measure or copies of a particular gene that is present in an organism. Abnormalities in the gene dosage at a particular location can cause severe damage to the resulting phenotype.
Gene dosage can lead to chromosome duplications if the copy number or gene product is more and it can cause deletions if the copy number or gene product is less. Such complications will result in abnormal phenotypes or inviable gametes. For example, in Down's syndrome, the person has a modification of the 21st chromosome as there is one extra 21st chromosome present. This leads to a variety of diseases and defects in the person.
Although a part of your question is missing, you might be referring to this question:
Chromosome duplications and deletions frequently result in abnormal phenotypes or inviable gametes. Which factor is a major contributor to this phenomenon?
a. Recessive diseases are unmasked by additional copies.
b. The genes are found in a novel arrangement.
c. Gene dosage is modified.
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Characteristics of Lancelets:
Small
Elongated
Marine invertebrate
Lacks a jaw
No sense organs
Has a notochord
Example: Lamprey
Characteristics of Tunicates:
Marine invertebrate
Has an outer coat that is rubbery or hard
Has two siphons
Examples: sea squirts, salps
I hope this is the answer that you were looking for.
Answer:
The genotype of both parents is RrYy.
The possible types of gametes would be RY, Ry, rY, and ry.
The cross would produce offspring that can have one out of four types of phenotypes:
- Round and yellow seeds (1 RRYY+ 2 RrYY +2 RRYy + 4 RrYy) = 9/16
- Wrinkled and yellow seeds (3 rrYy) = 3/16
- Round and green seeds (1 RRyy + 2 Rryy) = 3/16
- Wrinkled and green seeds (rryy) = 1/16
Thus, one out of 16 offspring would have wrinkled and green seeds.
Answer:
The correct answer would be:
A G C T
Human: 31 19 19 31
Cow: 28 22 22 28
Salmon: 29 21 21 29
Wheat 27 23 23 27
Yeast 31 19 19 31
Explanation:
According to the rule of Chargaff which states or explains the amount of the A, T, G, and C bases in the DNA molecule. It says that the DNA of any organism should have a pyrimidine and purine ratio of 1:1. This means the amount of A would be equal to T and the amount G should be equal to the amount of C.
It also says that the amount of a and G would be equal to the amount of C and T. So on the base of this we can find the missing value in the table:
A G C T
Human: 31 19 19 31 (A= T and G=C)
Cow: 28 22 22 28 (A= T and G=C)
Salmon: 29 21 21 29 (A= T and G=C)
Wheat 27 23 23 27 (100 - A+T = G+C)
Yeast 31 19 19 31 (A= T and G=C)
