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Digiron [165]
3 years ago
9

Pls help I dont understand. Find the inverse of this function.

Mathematics
1 answer:
lisov135 [29]3 years ago
8 0

In the inverse we replace the place of x by y .

g(x) =  \sqrt[3]{x}  - 3 \\  \\ x =  \sqrt[3]{y}  - 3 \\  \sqrt[3]{y}  = x + 3 \\ y =  {(x + 3)}^{3}  \\ y =  {(x + 3)}^{2} (x + 3) \\ y =  ({x}^{2}  + 6x + 9)(x + 3) \\ \\  y =  {x}^{3}  + 6 {x}^{2}  + 9x + 3 {x}^{2}  + 18x + 27 \\  \\ y =  {x}^{3}  + 9 {x}^{2}  + 27x + 27 \\   \\ \\ g(x)^{ - 1}  =  {x}^{3}  + 9 {x}^{2}  + 27x + 27

I hope I helped you^_^

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One possible equation is f(x) = (x + 3)\, (x - 5), which is equivalent to f(x) = x^{2} - 2\, x - 15.

Step-by-step explanation:

The factor theorem states that if x = x_{0}  (where x_{0} is a constant) is a root of a function, (x - x_{0}) would be a factor of that function.

The question states that (-3,\, 0) and (5,\, 0) are x-intercepts of this function. In other words, x = -3 and x = 5 would both set the value of this quadratic function to 0. Thus, x = -3\! and x = 5\! would be two roots of this function.

By the factor theorem, (x - (-3)) and (x - 5) would be two factors of this function.

Because the function in this question is quadratic, (x - (-3)) and (x - 5) would be the only two factors of this function. In other words, for some constant a (a \ne 0):

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Simplify to obtain:

f(x) = a\, (x + 3)\, (x - 5).

Expand this expression to obtain:

f(x) = a\, (x^{2} - 2\, x - 15).

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Every non-zero value of a corresponds to a distinct quadratic function with x-intercepts (-3,\, 0) and (5,\, 0). For example, with a = 1:

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