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Nadya [2.5K]
3 years ago
5

alt=" {x}^{2}{sin x}^{2} " align="absmiddle" class="latex-formula">
find its derivative​
Mathematics
1 answer:
suter [353]3 years ago
5 0

Answer:

2x(sinx^2 + x^2cosx^2).

Step-by-step explanation:

We use the product rule:

If u and v are functions of x then:-

d(uv)/dx = u dv/dx + v du/dx

So:

d(x^2 sinx^2)dx

=  x^2 * d(sinx^2)/dx + sinx^2 * d(x^2)/dx

= x^2 * 2xcosx^2 + sinx^2 * 2x

=  2x^3cosx^2 + 2xsinx^2

= 2x(sinx^2 + x^2cosx^2).

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A

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if not than it is not a function.

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