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3 years ago

Every 3 hours, a machine produces 60 baskets what is the unit rate

Mathematics

2 answers:

uranmaximum [27]3 years ago

8 0

Answer:

20 per hour

Step-by-step explanation:

divide 60 by 3=20

Pavel [41]3 years ago

8 0

Answer:

1:20

Step-by-step explanation:

if every 3 hours, the machine produces 60, then the ratio would be 3:60. to turn 3 into one to make it a unit rate, divide it by 3, then do the same to 60 to get 20. check to see if 3:60 is equal to 1:20 and it is so its correct.

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3 years ago

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2 years ago

At a carnival, 700 tickets were sold for a total

Diano4ka-milaya [45]

Answer:

The adult tickets are 400 and the children tickets are 300.

Step-by-step explanation:

Given:

At a carnival, 700 tickets were sold for a total amount of $5500. An adult ticket cost $10 and a children's ticket cost $5.

Now, to find the number of adult tickets and the number of children's tickets sold.

Let the number of adult tickets be $x.$

And let the number of children tickets be $y.$

So, the total number of tickets sold:

$x+y=700\\\\y=700-x\ \ \ ....(1)$

Now, the total amount of tickets:

$x(10)+y(5)=5500$

Substituting the value of $y$ from equation (1):

$x(10)+(700-x)(5)=5500\\\\10x+3500-5x=5500\\\\5x+3500=5500$

Subtracting both sides by 3500 we get:

$5x=2000$

Dividing boths sides by 5 we get:

$x=400.$

The number of adult tickets = 400.

Now, substituting the value of $x$ in equation (1) we get:

$y=700-x\\\\y=700-400\\\\y=300.$

The number of children tickets = 300.

Therefore, the adult tickets are 400 and the children tickets are 300.

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3 years ago

TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?

egoroff_w [7]

Answer:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

Step-by-step explanation:

$3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12$

Taking square root both sides, we get

$\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}$

Therefore, the values of $b$ are:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

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