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3 years ago

40 divided [24-4 x (2+3)]

1 answer:

3 0

$\frac{40}{24 - 4 * (2 + 3)} =\ \textgreater \ 
 \frac{40}{20 * (5)} =\ \textgreater \ 
 \frac{40}{100}$

Final answer .40

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Jeff has 1/4 of the pizza left

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Correct or no???????????,,

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A basketball coach kept stats for his team in free throw percentage and steals (among others). At the last game, Erin's free thr

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Answer:

Due to the higher z-score, she did better in the free throw category.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

She did better in the category that she had the higher z-score:

Free-throws:

Her free throw percentage was 79%, which means that $X = 79$

The team averaged 87% from the free throw line with a standard deviation of 12, which means that $\mu = 87, \sigma = 12$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{79 - 87}{12}$

$Z = -0.67$

Steals:

She had 4 steals, which means that $X = 4$

Averaged 7 steals with a standard deviation of 3, which means that $\mu = 7, \sigma = 3$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 7}{3}$

$Z = -1$

Due to the higher z-score, she did better in the free throw category.

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3 years ago

Five more than the product of four and a number is equal to the product of three and that same number increased by six.

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Answer:

The number is 1.

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A new sample of 225 employed adults is chosen. Find the probability that less than 7.1% of the individuals in this sample hold m

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Answer:

The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

Step-by-step explanation:

Let X = number of individuals in the United States who held multiple jobs.

The probability that an individual holds multiple jobs is, p = 0.13.

The sample of employed individuals selected is of size, n = 225.

An individual holding multiple jobs is independent of the others.

The random variable X follows a Binomial distribution with parameters n = 225 and p = 0.13.

But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion p.

Conditions of Normal approximation to Binomial are:

np ≥ 10
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Check the conditions as follows:

$np=225\times 0.13=29.25>10\\n(1-p)=225\times (1-0.13)=195.75>10$

The distribution of the proportion of individuals who hold multiple jobs is,

$p\sim N(p, \frac{p(1-p)}{n})$

Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:

$P(p$

*Use a z-table.

Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

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3 years ago