97.22 grams of magnesium is needed.
<u>Explanation:</u>
The molar ratio of Mg to O2 to make MgO is 2:1
Here, we have 2 moles of O2, therefore we need 4 moles of Mg.
1 mol of Mg = 24.305 g
Therefore
4 moles of Mg = 4 
24.305 g
= 97.22 g
Hence we need 97.22grams of magnesium are needed to completely reactwith 2.00 mol of O2 in the synthesis reaction that producesmagnesium oxide.
The product will not be affected by the addition of twice as much Na₂CO₃.
<h3>What is Limiting reagent in stoichiometry ?</h3>
- The maximum quantity of the end product determined by a balanced chemical equation is known as the Stoichiometry.
- The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced, and the one which remains unconsumed after the final reaction is in Excess.
- Calculate the moles of each reactant present and contrast it with the mole ratio of the reactants in the balanced equation to determine which reactant is the limiting one.
Here,taking the stoichiometry into consideration, we find that the reaction happens with 1:1 ratio; so, adding twice the amount of Na₂CO₃ will lead to its excess making the other the limiting reactant, hence, it would not affect the yield of the product.
To know more about the Limiting reactant, refer to:
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A lead ball added to a graduated cylinder containing 30.8 ml of water, causing the level of the water to increase to 89.9 ml, has a volume of 59.1 ml.
Volume is defined as the amount of space that matter occupies. There are three different ways to find the volume:
1) Volume by Space - by measuring its physical dimensions
2) Volume by Density and Mass - by dividing its weight by its density
3) Volume by Displacement - by measuring the volume displaced when immersed in a liquid or gas
To solve for the volume of the lead ball, we can use the displacement method by subtracting the initial volume from the final volume.
If the level of the water increased from 30.8 ml to 89.9 ml upon adding the lead ball, the displaced volume is:
volume = final volume - initial volume
volume = 89.9 - 30.8
volume = 59.1 ml
Hence, the volume of the lead ball, using displacement method, is 59.1 ml.
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Answer:
Sulfuric acid (H2SO4) contains:
2 Hydrogen 1 Sulfer
4 Oxygen
Explanation:
