Answer:
Explanation:
To isolate a single variable when rearranging equations, move all other variables to the other side of the equation by using its inverse operation on them and remembering to perform that operation on itself. Make sure the rearrangement has the target variable. For example, we can grab a simple equation such as the one below and isolate x.
x - 5y + 3 = 25 ... first we subtract 3 from both sides
x - 5y = 22 ... now we add 5y to both sides which will cancel out the 5y on the left
x = 22 + 5y
And we finally have the x variable isolated.
This is a simple problem where you would use the simplified formula
P = m • v
16 kgm/s = 8 kg • v
V = 2 m/s.
The ball is travelling at 2 m/s.
Answer:
(A) The shorter the wavelength, the more total energy the wave contains.
(B) The longer the wavelength, the less total energy the wave contains.
Explanation:
The wavelength (λ), frequency (f) and energy (E) are interrelated. This relationship between them is represented in the following equations:
λ = v/f and E = hf
Where;
λ = wavelength (m)
f = frequency (Hz)
E = energy (Joules)
v and h represents speed of light and Planck's constants respectively.
Combining both equations, E = hc/λ
This equation shows that ENERGY (E) is directly proportional to the frequency (f) but inversely proportional to the wavelength (λ). This means that "the shorter the wavelength, the more total energy a wave contains" and vice versa.
However, the higher the frequency, the more the total energy the wave contains and vice versa.
Answer:
1.The electrode on the right is positive
2. 0.058V
Explanation:
The above cell is a concentration cell.
A concentration cell is an electrolytic cell that is made of two half-cells with the same electrodes, but differs in concentrations of the solutions. A concentration cell functions by diluting the more concentrated solution and concentrating the more dilute solution, creating a voltage as the cell reaches an equilibrium thereby transferring the electrons from the cell with the lower concentration to the cell with the higher concentration.
In the above cell, electrons flow from the left electrode (less concentrated) to the right electrode (more concentrated). Therefore, the right electrode is the positive electrode (cathode).
Part 2: Please, see the attachment below for the calculations.
